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Nadya [2.5K]
3 years ago
7

A large bowl contains 10 small balls and each ball has a color and a number. The 10 balls are denoted by B1, B2, B3, B4, R1, R2,

R3, G1, G2, G3, where B1 denotes a blue ball with the number 1, R1 denotes a red ball with the number 1, G2 denotes a green ball with the number 2, and so on. Two balls are drawn from the bowl at random, one after the other, without replacement. Let B3R1 denote B3 on the first draw and R1 on the second draw. Note that B4B4 is not possible since the draws are without replacement. (a) Let S be the sample space. What is the size of the set S, N(S)?
Mathematics
1 answer:
nasty-shy [4]3 years ago
4 0

Answer:

Size of N(S) = 90, or S=90

Step-by-step explanation:

So since there are 10 items:

Each single item has 9 possibilities to be paired with, since it is drawn without replacement, and 1 item can't be drawn again.

So : 10 items x 9 possibilites = array of 90

SO ANSWER : 90

Hope I helped :)

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