1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
V125BC [204]
3 years ago
14

HELPPPPPPP PLEASE 5 MINUTES LEFT

Mathematics
1 answer:
iren [92.7K]3 years ago
7 0
The answer is 118 hope this helps
You might be interested in
The difference between a number and 8
stich3 [128]

Answer:

n-8

Step-by-step explanation:

The difference between a number and 8

Difference is subtraction

Let the number be n

n-8

3 0
3 years ago
Use undetermined coefficient to determine the solution of:y"-3y'+2y=2x+ex+2xex+4e3x​
Kitty [74]

First check the characteristic solution: the characteristic equation for this DE is

<em>r</em> ² - 3<em>r</em> + 2 = (<em>r</em> - 2) (<em>r</em> - 1) = 0

with roots <em>r</em> = 2 and <em>r</em> = 1, so the characteristic solution is

<em>y</em> (char.) = <em>C₁</em> exp(2<em>x</em>) + <em>C₂</em> exp(<em>x</em>)

For the <em>ansatz</em> particular solution, we might first try

<em>y</em> (part.) = (<em>ax</em> + <em>b</em>) + (<em>cx</em> + <em>d</em>) exp(<em>x</em>) + <em>e</em> exp(3<em>x</em>)

where <em>ax</em> + <em>b</em> corresponds to the 2<em>x</em> term on the right side, (<em>cx</em> + <em>d</em>) exp(<em>x</em>) corresponds to (1 + 2<em>x</em>) exp(<em>x</em>), and <em>e</em> exp(3<em>x</em>) corresponds to 4 exp(3<em>x</em>).

However, exp(<em>x</em>) is already accounted for in the characteristic solution, we multiply the second group by <em>x</em> :

<em>y</em> (part.) = (<em>ax</em> + <em>b</em>) + (<em>cx</em> ² + <em>dx</em>) exp(<em>x</em>) + <em>e</em> exp(3<em>x</em>)

Now take the derivatives of <em>y</em> (part.), substitute them into the DE, and solve for the coefficients.

<em>y'</em> (part.) = <em>a</em> + (2<em>cx</em> + <em>d</em>) exp(<em>x</em>) + (<em>cx</em> ² + <em>dx</em>) exp(<em>x</em>) + 3<em>e</em> exp(3<em>x</em>)

… = <em>a</em> + (<em>cx</em> ² + (2<em>c</em> + <em>d</em>)<em>x</em> + <em>d</em>) exp(<em>x</em>) + 3<em>e</em> exp(3<em>x</em>)

<em>y''</em> (part.) = (2<em>cx</em> + 2<em>c</em> + <em>d</em>) exp(<em>x</em>) + (<em>cx</em> ² + (2<em>c</em> + <em>d</em>)<em>x</em> + <em>d</em>) exp(<em>x</em>) + 9<em>e</em> exp(3<em>x</em>)

… = (<em>cx</em> ² + (4<em>c</em> + <em>d</em>)<em>x</em> + 2<em>c</em> + 2<em>d</em>) exp(<em>x</em>) + 9<em>e</em> exp(3<em>x</em>)

Substituting every relevant expression and simplifying reduces the equation to

(<em>cx</em> ² + (4<em>c</em> + <em>d</em>)<em>x</em> + 2<em>c</em> + 2<em>d</em>) exp(<em>x</em>) + 9<em>e</em> exp(3<em>x</em>)

… - 3 [<em>a</em> + (<em>cx</em> ² + (2<em>c</em> + <em>d</em>)<em>x</em> + <em>d</em>) exp(<em>x</em>) + 3<em>e</em> exp(3<em>x</em>)]

… +2 [(<em>ax</em> + <em>b</em>) + (<em>cx</em> ² + <em>dx</em>) exp(<em>x</em>) + <em>e</em> exp(3<em>x</em>)]

= 2<em>x</em> + (1 + 2<em>x</em>) exp(<em>x</em>) + 4 exp(3<em>x</em>)

… … …

2<em>ax</em> - 3<em>a</em> + 2<em>b</em> + (-2<em>cx</em> + 2<em>c</em> - <em>d</em>) exp(<em>x</em>) + 2<em>e</em> exp(3<em>x</em>)

= 2<em>x</em> + (1 + 2<em>x</em>) exp(<em>x</em>) + 4 exp(3<em>x</em>)

Then, equating coefficients of corresponding terms on both sides, we have the system of equations,

<em>x</em> : 2<em>a</em> = 2

1 : -3<em>a</em> + 2<em>b</em> = 0

exp(<em>x</em>) : 2<em>c</em> - <em>d</em> = 1

<em>x</em> exp(<em>x</em>) : -2<em>c</em> = 2

exp(3<em>x</em>) : 2<em>e</em> = 4

Solving the system gives

<em>a</em> = 1, <em>b</em> = 3/2, <em>c</em> = -1, <em>d</em> = -3, <em>e</em> = 2

Then the general solution to the DE is

<em>y(x)</em> = <em>C₁</em> exp(2<em>x</em>) + <em>C₂</em> exp(<em>x</em>) + <em>x</em> + 3/2 - (<em>x</em> ² + 3<em>x</em>) exp(<em>x</em>) + 2 exp(3<em>x</em>)

4 0
2 years ago
Please help me with this question<br><br><br><br> pls, I really need help
Inessa [10]
Answer: x=7, y=-23
(7,-23)

Explanation:

4 0
2 years ago
Assume that Santa has to deliver presents to almost 22 million kids an hour on the night before Christmas. What is his delivery
DENIUS [597]

Answer:

It's about 6,111 kids per second.

Step-by-step explanation:

1 hour = 60 minutes

1 minute = 60 seconds

60*60=3600

1 hour = 3600

hourly rate -> 22,000,000 kids/hr

secondly rate -> 22,000,000/3600 ≈ 6,111

secondly rate -> 6,111 kids/second

7 0
3 years ago
Please help me with thiss
olchik [2.2K]

Answer:

gradient = 2

Step-by-step explanation:

Calculate the gradient (slope) m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (1, 0) and (x₂, y₂ ) = (6, 10) ← 2 points on the line

m = \frac{10-0}{6-1} = \frac{10}{5} = 2

3 0
2 years ago
Other questions:
  • HELP QUICK GIVING 50 POINTS!!!
    11·1 answer
  • The cost of two tables and three chairs is 705$ if the table costs 40$ more than the chair find the cost of one table and two ch
    8·1 answer
  • Determine the vertex and the axis of symmetry for the function below <br> Y=x^2+4x+1
    13·1 answer
  • 0.932 g = ----------- mg​
    5·2 answers
  • How do I simplify (tanx/1+secx) + (1+secx/tanx)
    9·1 answer
  • Find the Quotient.<br> 1,382 divided 4
    12·1 answer
  • Plzzzzzzzz helpe out​
    11·2 answers
  • <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20-%202%20%2B%203%20%5Ctimes%206%7D%205" id="TexFormula1" title=" \frac{ - 2 + 3
    11·2 answers
  • Write the equation of this line
    7·1 answer
  • A linear function has the table of values shown. The information in the table shows the number of tickets sold on opening night
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!