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const2013 [10]
3 years ago
5

What is the slowest shutter speed?

Computers and Technology
1 answer:
crimeas [40]3 years ago
7 0

Answer: I think the answer would be 1/30 or 1/60

Explanation: Anything below 1/90 is considered a soft image so i would go with 1/30 Brainliest ans plz.

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Header and footer elements such as worksheet name, current date, and time are _____ elements, they change as your worksheet does
mario62 [17]
<span>Header and footer elements such as worksheet name, current date, and time are dynamic elements, they change as your worksheet does. Because the information they </span><span>contain ( page number, date,) changes that's why they are dynamic. Otherwise if the information was fixed, they would be static elements.</span>
7 0
3 years ago
Complete the steps for saving a presentation as a poi file,
mars1129 [50]

Answer:

Click on the F

Copy & Print

Next, click on

Last, click

Send

Save As

Explanation:

This is because save means it will save your file as the same you have made but drop do means to cut or don't save the file that's why it should be the second one means:Click on the F

Copy & Print

Next, click on

Last, click

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4 0
3 years ago
What are the two most important network-layer functions in a datagram network? what are the three most important network-layer f
PIT_PIT [208]
1. Datagram-based network layer: Forwarding, Routing.
2. VC- based network layer: Forwarding, Routing, Call setup.
7 0
3 years ago
PLEASE HELP THIS WAS DUE YESTERDAY AND I DIDN'T GET TO IT IN TIME!!!!!!
kykrilka [37]

Answer:

dDAgv

Explanation:

sdc sdc sdc trust me

7 0
3 years ago
Write a program that takes a point (x,y) from theuser and find where does the point lies. The pointcan
agasfer [191]

Answer:

C++ Program .

#include<bits/stdc++.h>

using namespace std;

int main()

{

int x,y;//declaring two variables x and y.

string s;//declaring string s..

cout<<"enter x and y"<<endl;

cin>>x>>y;//taking input of x and y..

if(x>=0 &&y>=0) //condition for 1st quadrant..

cout<<"the point lies in 1st Quadrant"<<endl;

else if(x<=0 &&y>=0)//condition for 2nd quadrant..

cout<<"the point lies in 2nd Quadrant"<<endl;

else if(x>=0 &&y<=0)//condition for 3rd quadrant..

cout<<"the point lies in 3rd Quadrant"<<endl;

else //else it is in  4th quadrant..

cout<<"the point lies in 4th Quadrant"<<endl;

cout<<"enter n to terminate the program"<<endl;

while(cin>>s)//if the user has not entered n the program will not terminate..

{

   if(s=="n")

   {

       cout<<"the program is terminated"<<endl;

       exit(0);

   }

   cout<<"you have not entered n please enter n to terminate the program<<endl;

}

}

Explanation:

The above written program is for telling the point lies in which quadrant.I am first declaring two variables x and y.Then after that taking input of x and y after that checking in which quadrant the point lies.

Taking input of the string s declared earlier for program termination the program will keep running until the user enters n.

4 0
3 years ago
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