Answer:
Back up the user data to removable disk
Explanation:
Before you work on a computer, especially anything that has to do with files not accessible, this might need to format the system because it might either be a virus or other forms of malware. Since backup was done to a different logical partition on the disk, the first thing to do before performing any diagnostic procedures on the disk is to back up the user data to a removable disk in order not to lose the information in the system.
Options A and C can get you confused. We can choose option A if our argument is based entirely on digital images. The correct answer, however, is C: Number of pixels you see on your computer monitor.
Resolution describes the clarity and sharpness of a picture that can be measured by the number of pixels contained on a display monitor. It can be expressed by the number of horizontal (width) and vertical pixels (height) represented by a screen. The clarity and sharpness are always dependent on the resolution and size of the monitor.
Answer:
In a <u>little endian computer</u> -The data's least substantial byte is put at the lower address byte. The remaining information will be put in memory in order in the next three bytes.
a)1234
4 is placed at the least significant bits,so this byte stored at lower memory address.
1 is placed at the most significant bits,so this byte stored at higher memory address.
b) ABFC
C is placed at the least significant bits,so this byte stored at lower memory address.
A is placed at the most significant bits,so this byte stored at higher memory address.
c) B100
0 is placed at the least significant bits,so this byte stored at lower memory address.
B is placed at the most significant bits,so this byte stored at higher memory address.
d) B800
0 is placed at the least significant bits,so this byte stored at lower memory address.
B is placed at the most significant bits,so this byte stored at higher memory address.
Answer:
see explaination
Explanation:
MaxArray.java
public class MaxArray{
public static void main(String[] args) {
int a[] = {1,2,5,4,3};
int max = max (a, 5);
System.out.println("Max value is "+max);
}
public static int max (int a[],int size){
if (size > 0) {
return Math.max(a[size-1], max(a, size-1));
} else {
return a[0];
}
}
}
Output:
MaxArray
