Given a plane:
normal vector <2,4,-3>
passes through point (-1,3,5)
The equation of the plane is
Π : 2(x-(-1))+4(y-3)-3(z-5)=0
expand and simplify
Π : 2x+4y-3z+5=0
I hope and think it’s 12015
Because this what I did I (.89)x
And x = 13500 and I got 12015
Answer:
the submarine is 92.994 feet ≈ 93 feet deep from the surface of the water
Step-by-step explanation:
We can think in a triangle where the hypotenuse is the detection distance and the angle with the horizontal surface of water is the depression angle, then the underwater distance is the vertical side of the triangle.
If we denote Ф as the angle of depression ,d as the detection distance and x as the unknown depth of the submarine, using trigonometry:
x = d* sin Ф
thus
x= d * sin Ф = 238 feet * sin 23° = 92.994 feet ≈ 93 feet
Answer:
1/4
Step-by-step explanation:
Hope this helps!
Diagonals congruent: rectangle, square, isosceles trapezoid
Perpendicular bisectors: Rhombus, Square
