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SSSSS [86.1K]
3 years ago
15

When planning her crops, Farmer Sue knows that her 15 acres can support apples and pecans. She wants to make $8,500 from her cro

ps. She can make $1,050 per acre of apples (the variable a) and $2,500 per acre of pecans (the variable p). Which equation below would be a constraint in her system of equations? (1 point)
Mathematics
1 answer:
irakobra [83]3 years ago
5 0

Answer:

2500p+1050a=8500

Step-by-step explanation:

You want combinations of pecans to apples to equal $8500 and you know how much money you make per acre.

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1/2x=8 as a mixed number show work​
olga nikolaevna [1]

Answer:

16

Step-by-step explanation:

1/2 x =8

Multiply both sides by 2

x = 8 times 2

x = 16

5 0
3 years ago
Read 2 more answers
(-5x^6+7x+1)-(8x^2+x-10)<br><br> Algebra 1 subtracting polynomials please help
BaLLatris [955]

Answer:

-5x^6-8x^2+6x+11

Step-by-step explanation:

(-5x^6+7x+1)-(8x^2+x-10)

Remove parentheses

-5x^6+7x+1-(8x^2+x-10)

-(8x^2+x-10)=-8x^2-x+10

-5x^6+7x+1-8x^2-x+10

Simplify

-5x^6-8x^2+6x+11

5 0
3 years ago
Two supplementary angles are in the ratio 3 1 : 5 find both angles​
Zielflug [23.3K]

The two angles are 155 degrees and 25 degrees

<h3><u>Solution:</u></h3>

Given that two supplementary angles are in ratio 31 : 5

Let the first angle be 31a

Let the second angle be 5a

Two Angles are Supplementary when they add up to 180 degrees.

Therefore,

first angle + second angle = 180 degrees

31a + 5a = 180\\\\36a = 180\\\\a = \frac{180}{36}\\\\a = 5

<em><u>Therefore the angles are:</u></em>

first angle = 31a = 31(5) = 155 degrees

second angle = 5a = 5(5) = 25 degrees

Thus the two angles are 155 degrees and 25 degrees

3 0
3 years ago
Consider U = {x\x is a real number}
zysi [14]

Answer:

The fourth pair of statement is true.

9∈A, and 9∈B.

Step-by-step explanation:

Given that,

U={x|  x is real number}

A={x| x∈ U and x+2>10}

B={x| x∈ U and 2x>10}

  • 5 ∈ A , 5 ∈ B

If 5∈ A, Then it will be satisfies x+2>10 , but 5+2<10.

Similarly, If 5∈ B, Then it will be satisfies 2x>10 , but 2.5=10.

So, 5∉A, and 5∉B.

  • 6 ∈ A , 6 ∈ B

If 6∈ A, Then it will be satisfies x+2>10 , but 6+2<10.

Similarly, If 6∈ B, Then it will be satisfies 2x>10 , and 2.6=12>10.

So, 6∉A, and 6∈B.

  • 8 ∈ A , 8 ∈ B

If 8∈ A, Then it will be satisfies x+2>10 , but 8+2=10.

Similarly, If 8∈ B, Then it will be satisfies 2x>10.  2.8=16>10.

So, 8∉A, and 8∈B.

  • 9 ∈ A , 9 ∈ B

If 9∈ A, Then it will be satisfies x+2>10 , but 9+2=11>10.

Similarly, If 9∈ B, Then it will be satisfies 2x>10.  2.9=18>10.

So, 9∈A, and 9∈B.

3 0
2 years ago
O NEED HELP QUICK!!!
Wittaler [7]

Answer:

the third one is your answer

Step-by-step explanation:

5 0
2 years ago
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