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3 years ago

What factors do the numbers 20 and 30 have in common?

Mathematics

2 answers:

Amiraneli [1.4K]3 years ago

6 0

Answer:

B. 1, 2, 5, 10

Step-by-step explanation:

Vikki [24]3 years ago

3 0

I think it’s c I hope this works for you

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Suzanne is 64 inches tall. What is Suzannes height in feet and inches

Elodia [21]

There's 12 inches in 1 foot.

64 ÷ 12 = 5 with a remainder of 4

Suzanne is 5 foot 4 inches.

Hope this helps.

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3 years ago

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I a, very confused on what the answer is to blank- 3/10=1/5

Yuri [45]

Answer:

a = 1/2

Step-by-step explanation:

a - 3/10 = 1/5

Add 3/10 to each side

a - 3/10 +3/10 = 1/5+3/10

a = 1/5+3/10

Get a common denominator

a= 1/5*2/2 +3/10

a = 2/10 +3/10

a = 5/10

Divide the top and bottom by 5

a = 1/2

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3 years ago

What is the value of n in n/0.38= 5.89

Marianna [84]

N=1191/5000 or 2.238

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3 years ago

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The spinner shown below is used to play a game.

Westkost [7]

The probability is 3/8

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3 years ago

Simplify the expression below and write it as a single logarithm:

OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is $\log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

<u>Solution:</u>

Given, expression is $3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

$\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

Rearranging the terms we get,

$\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)$

$\text { since a } \times \log b=\log \left(b^{a}\right)$

$\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)$

$\text { We know that } \log a \times \log b=\log a b$

$\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.$

$\text { We know that } \log a-\log b=\log \frac{a}{b}$

$\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

Hence, the simplified form $\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

4 0

3 years ago

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