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RoseWind [281]
4 years ago
13

25% of 80 = what percent???

Mathematics
2 answers:
Harrizon [31]4 years ago
5 0

Answer:

25% of 80 = 20

Step-by-step explanation:

As given

80*25%

=80*25/100

=80*1/4

=80/4

=20

Doss [256]4 years ago
4 0

First off, you really don't need to write "what percent???" here.  

25% of 80 is 0.25(80) = 20.  

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2x = 48
x =;24. Sonia
x+15 = 39. Sophia
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Roxy claims that the product of any fraction and 1818 will always be less than 1818.
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A school has 200 students and spends $40 on supplies for each student. The principal expects the number of students to increase
Xelga [282]

Answer:

\mathbf{S(t)=200(\frac{105}{100})^{x}}

\mathbf{A(t)=40(\frac{98}{100})^{x}}

\mathbf{E(t)=S(t) \cdot A(t)=200(\frac{105}{100})^{x} \cdot 40(\frac{98}{100})^{x}=8000(\frac{10290}{10000})^{x}}

Step-by-step explanation:

<h3>The predicted number of students over time, S(t) </h3>

Rate of increment is 5% per year.  

A function 'S(t)' which gives the number of students in school after 't' years.  

S(0) means the initial year when the number of students is 200.

S(0) = 200  

S(1) means the number of students in school after one year when the number increased by 5% than previous year which is 200.  

S(1) = 200 + 5% of 200 = 200+\frac{5}{100}\time200 = 200(1+\frac{5}{100}) = 200(\frac{105}{100})  

S(2) means the number of students in school after two year when the number increased by 5% than previous year which is S(1)  

S(2) = S(1) + 5% of S(1) = \textrm{S}(1)(\frac{105}{100}) = 200(\frac{105}{100})(\frac{105}{100}) = 200(\frac{105}{100})^{2}  

.  

.  

.  

.  

.  

Similarly \mathbf{S(x)=200(\frac{105}{100})^{x}}  

<h3>The predicted amount spent per student over time, A(t) </h3>

Rate of decrements is 2% per year.  

A function 'A(t)' which gives the amount spend on each student in school after 't' years.  

A(0) means the initial year when the number of students is 40.  

A(0) = 40  

A(1) means the amount spend on each student in school after one year when the amount decreased by 2% than previous year which is 40.  

A(1) = 40 + 2% of 40 = 40-\frac{2}{100}\time40 = 40(1-\frac{2}{100}) = 40(\frac{98}{100})  

A(2) means the amount spend on each student in school after two year when the amount decreased by 2% than previous year which is A(1)  

A(2) = A(1) + 2% of A(1) = \textrm{A}(1)(\frac{98}{100}) = 40(\frac{98}{100})(\frac{98}{100}) = 40(\frac{98}{100})^{2}  

.  

.  

.  

.  

.  

Similarly \mathbf{A(x)=40(\frac{98}{100})^{x}}  

<h3>The predicted total expense for supplies each year over time, E(t)</h3>

Total expense = (number of students) ×  (amount spend on each student)

E(t) = S(t) × A(t)

\mathbf{E(t)=S(t) \cdot A(t)=200(\frac{105}{100})^{x} \cdot 40(\frac{98}{100})^{x}=8000(\frac{10290}{10000})^{x}}

\mathbf{E(t)=8000(\frac{10290}{10000})^{x}}

(NOTE : The value of x in all the above equation is between zero(0) to ten(10).)

6 0
3 years ago
Read 2 more answers
Solve x + 3y = 9<br> 3x − 3y = −13
Minchanka [31]
X + 3y = 9
3x - 3y = -13
--------------add
4x = - 4
x = -4/4
x = -1

x + 3y = 9
-1 + 3y = 9
3y = 9 + 1
3y = 10
y = 10/3

solution (-1,10/3)
5 0
3 years ago
Read 2 more answers
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