The answer should be if I am correct
h times 5.25
First, put parenthesis around the first two numbers and the last two numbers.
(20g³+24g²) (-15g-18)
Then, take out the greatest common factor of both parenthesis.
4g²(5g+6)-3(5g+6)
You then separate the numbers outside the parenthesis and the numbers in the parenthesis.
(5g+6) (4g²-3)
Then you simplify the second set of numbers. Since the set of numbers can't be simplified, you would leave this problem as it is. I hope this makes sense.
5 times as many. Since dog B has 2 and dog A has 10, A = 2 * X, since you’re solving for the multiplication comparison. 10/2 = 5, so you’ve got 5 times as many.
g(x) = x - 3 = 0
g(x) = x = 3
f(x) = 2x^3 + x - 4
f(3) = 2(3)^3 + 3 - 4
f(3) = 2(27) - 1
f(3) = 54 - 1
f(3) = 53
The remainder when f(x) is divided by x - 3 is <u>53</u>.
