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Neporo4naja [7]
3 years ago
8

A = bh/2

Mathematics
1 answer:
Sliva [168]3 years ago
6 0
To find A' they used the rule of multiplication, which is:

the derivative of a product of two terms is the first term times the derivative of the second term plus the second term times the derivative of the first.

To find b' they just isolated b'


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2.) The equation yˆ=−8.74x2+50.57x+39.02 models the number of customers in a store x hours after opening.
Artemon [7]

Answer:

2. The correct option is;

D. 112

3. The predicted number of cellular subscription per 100 people in Australia in 2030 is 217 subscriptions

4. The equation of the quadratic regression curve is y = x² - 6×x + 4.1

5. The closest option is;

C. 4191

Step-by-step explanation:

2. The equation for the number of customers in a store is presented as follows;

y = -8.74·x² + 50.57·x + 39.02

Where:

x = Number of hours after opening

∴ When x = 3 hours

y = -8.74×3² + 50.57×3 + 39.02 = 112.07 ≈ 112 people

The correct option is D. 112

3. The expression of the regression equation is presented as follows

y = -0.107·x² + 9.008·x +28.851

Where:

x = Number of years since 1990, hence

When x = 2030 - 1990 = 40 Years

Hence, the predicted number of cellular subscriptions per  people in 2030 is presented as follows;

y = -0.107×40² + 9.008×40 +28.851 = 217.971 Subscribers

To round down to the nearest whole number as y = 217 subscribers

4. The general form of a quadratic equation is presented as follows;

y = a·x² + b·x + c

When x = 0, y = 4.1, therefore;

4.1 =  a×0² + b×0 + c = c

∴ c = 4.1

When x = 1, y = -0.9, therefore;

-0.9 =  a×(1)² + b×1 + c = c

-0.9 =  a + b + 4.1

∴ a + b = -0.9 - 4.1 = -5.0

When x = 2, y = -3.9, therefore;

-3.9 =  a×(2)² + b×2 + c = c

-3.9 =  4·a + 2·b + 4.1

∴ 4·a + 2·b = -3.9 - 4.1 = -8.0

Thus we have two equations;

a + b = -5.0..................(1) and

4·a + 2·b = -8.0 ..........(2)

Multiply equation (1) by 2 and subtract it from equation (2), we have

4·a + 2·b - 2×(a + b) = *8.0 - (2 ×-5.0)

∴ 2·a = 2

a = 1

From equation (1,)  we have;

a + b = -5.0..................(1)

Therefore, where a = 1 we have, 1 + b = -5.0

Hence, b = -5.0  - 1 = -6.0

Therefore, the equation of the quadratic regression curve is presented as follows;

y = x² - 6×x + 4.1

5. The quadratic regression equation is found as follows;

The general form of a quadratic equation is presented as follows;

y = a·x² + b·x + c

When x = 55, y = 3650, therefore;

3650=  a×55² + b×55+ c................(1)

When x = 65, y = 4569, therefore;

4569=  a×65² + b×65+ c ...........(2)

When x = 75, y = 6147, therefore;

6147=  a×75² + b×75+ c............(3)

Solving the system of equation;

3650=  a×55² + b×55+ c................(1)

4569=  a×65² + b×65+ c ...........(2)

6147=  a×75² + b×75+ c............(3)

Subtracting equation (1) from (2), we obtain;

4569 - 3650 =  a×65² + b×65 + c - (a×55² + b×55 + c)

919 = 1200·a + 10·b...........(4)

Subtracting equation (2) from (3), we obtain;

6147 - 4569 =  a×75² + b×75 + c - (a×65² + b×65+ c)

Which gives;

1578 = 1400·a + 10·b...........(5)

Subtracting equation (4) from equation (3), we obtain;

1578 - 919 = 1400·a + 10·b - (1200·a + 10·b)

659 = 200·a

a = 659/200= 3.295

Substituting the value of a in equation (4), we have;

919 = 1200×3.295 + 10·b = 3954 + 10·b

∴ 10·b = 919 -3954 = -3035

b = -3035/10 = -303.5

Substituting the value of a and b in equation (1), we have;

3650 =  (3.295)×55² + (-303.5)×55+ c

3650 = -6725.125 + c

∴ c = 3650 - (- 6725.125)= 10375.125

Therefore, the quadratic regression equation is presented as follows;

y = 3.295·x - 303.5·b +10375.125

Hence, in 1961, x = 1961 - 1900 = 61, we have

y = 3.295×61² - 303.5×61 10375.125= 4122.32

Therefore, the closest option is C. 4191.

7 0
3 years ago
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