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3 years ago

Someone help me please! will give brainliest.

Mathematics

1 answer:

Monica [59]3 years ago

4 0

Answer: Graph B and Graph D

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G(x)=−3x−8<br><br> g( )=10<br><br> what's in the parenthesis

Kazeer [188]

Answer:

Step-by-step explanation:

G(x)=-3x-8
x + 3x= -8

4x=8

x= $\frac{8}{4}$

x=2
G(2)=10
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5 0

2 years ago

Teresa is going for a run. she runs for 9.6 miles at a speed of 6 miles per hour. for how many hours does she run?

Lera25 [3.4K]

Speed=6 miles per hour
Distance =9.6 miles
Speed =distance /time
Time=distance/speed=9.6/6=1.6 hours

7 0

4 years ago

Answer this for me please gotta hurry!! 4x10^-2

Nitella [24]

Answer: 0.04

Step-by-step explanation:

Because I calculated it.

3 0

3 years ago

Read 2 more answers

NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions

Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector $\vec{v}$ in some vector space $\mathbb R^n$ we have

$\vec{v} = \langle a,b\rangle$

This is the component form. I don't like that way. It is probably used in high school, but

$\vec{v} = \begin{pmatrix} a\\ b\\ \end{pmatrix}$

is preferable because the inner product on $\mathbb R^n$ is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as $\vec{v} = 2i+2j$

For this question, I think you meant

vectors

$\vec{u_1} = (-8, 12)$

$\vec{u_2} = (13, 15)$

Once

$\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}$

Considering that the dot product is

$\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76$

and the norm of $\vec{u_1}$ is $||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}$

and the norm of $\vec{u_2}$ is $||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}$

Thus,

$\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}$

$\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)$

3 0

3 years ago

Look at the picture

ValentinkaMS [17]

Answer: 54

Step-by-step explanation:

3 times the square of -3 plus -5 times -3 plus 12

3 times 9 + 15 + 12

27+15+12=

7 0

3 years ago