A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>
Answer:
70 + 5 + 8/10 + 6/100 + 4/1000
Or
7*10 + 5*1 + 8*1/10 + 6*1/100 + 4*1/1000
100 + 8d = 300; d = 25; The kitten will triple its weight in 25 days
Answer:
His error is multiplying by 4 sides as he thought it was total surface not lateral surface area- the final answer is 12
Step-by-step explanation:
He should have multiplied it by 3, because the 3 sides- not including the base- is what lateral surface area is. He originally did total surface area not lateral surface area so each sides area is 4m squared then you just multiply it by 3 and its 12
Answer:
girl im over here trying to find the same answer
Step-by-step explanation:
