Remember that the vertex form of a parabola or quadratic equation is:
y=a(x-h)^2+k, where (h,k) is the "vertex" which is the maximum or minimum point of the parabola (and a is half the acceleration of the of the function, but that is maybe too much :P)
In this case we are given that the vertex is (1,1) so we have:
y=a(x-1)^2+1, and then we are told that there is a point (0,-3) so we can say:
-3=a(0-1)^2+1
-3=a+1
-4=a so our complete equation in vertex form is:
y=-4(x-1)^2+1
Now you wish to know where the x-intercepts are. x-intercepts are when the graph touches the x-axis, ie, when y=0 so
0=-4(x-1)^2+1 add 4(x-1)^2 to both sides
4(x-1)^2=1 divide both sides by 4
(x-1)^2=1/4 take the square root of both sides
x-1=±√(1/4) which is equal to
x-1=±1/2 add 1 to both sides
x=1±1/2
So x=0.5 and 1.5, thus the x-intercept points are:
(0.5, 0) and (1.5, 0) or if you like fractions:
(1/2, 0) and (3/2, 0) :P
Answer:

Step-by-step explanation:
![\sqrt{5} \times \sqrt{10} \\ = \sqrt{5} \times \sqrt[]{5} \times \sqrt{2} \\ = 5\sqrt{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B5%7D%20%20%5Ctimes%20%20%5Csqrt%7B10%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B5%7D%20%20%5Ctimes%20%20%5Csqrt%5B%5D%7B5%7D%20%20%5Ctimes%20%20%5Csqrt%7B2%7D%20%20%5C%5C%20%20%20%3D%205%5Csqrt%7B2%7D%20)
<h3>Hope it is helpful....</h3>
Answer:
86.16
Step-by-step explanation:
27+3÷ 3 +4-1+72.4-34.24+6-4+75÷5
PEMDAS
Multiply and divide first
3/3 is 1 and 75/5 = 15
Replace these into the equation
27+1 +4-1+72.4-34.24+6-4+15
Then add and subtract from left to right
31 +72.4-34.24+6-4+15
69.16+6-4+15
86.16
Good evening,
Step-by-step explanation:
Look at the photo below for the Answer.
:)
statements:
1.) E is midpoint of TP
2) TP bisects MR
reasons:
1.)given
2) MT is congruent to PR (I think)
I might be wrong though so dont count on it being right. I hope I helped. ime not that good at math. I m not BAD but yea