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3 years ago

Trapezoid JKLM is shown on the coordinate plane below:

2 answers:

5 0

Well, if I'm reading this correctly, your first trapezoid has coordinates:
J(-2, 1), K(1, 1), L(3, -2), and then M(-4, -2).
Now it gives you the transition equation for how the trapezoid would move which is: (x, y) -> (x + 5, y - 4)
Since you are looking for L, simply place L's coordinates inside:
L = (3 + 5, -2 - 4) -
Now solve it. L = (8, -6) -
This should be the new set of coordinates for L.

Veseljchak [2.6K]3 years ago

3 0

Answer: ( 1, -4 )

Step-by-step explanation: Just did the test.

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Truck has a trailer that has a length of 13 feet width of 6 feet and a height of 8 feet what is the volume of the trailer

Nezavi [6.7K]

Answer:

624ft^3

Step-by-step explanation:

the formula for volume is lengthxwidthxheight.

so it would be 13x6x8

and that sum is 624ft^3

6 0

3 years ago

What is the y-intercept of the function f(x)=4 – 5x? A:-5 B:-4 C:4 D:-5

Bogdan [553]

Answer: option C is the correct answer

Step-by-step explanation:

The y-intercept of the function is the point on the y or vertical axis at which the straight line cuts through it. The value on the y axis is read off as the y-intercept .

The equation of a straight line is modelled using the slope - intercept equation of

y = mx + c

Where m is the slope( change in value of y/ change in value of x.

c = the y-intercept

Looking at the function given,

f(x)=4 – 5x? Where f(x) is the same as y in our slope intercept equation.

Rearranging the function, it becomes

f(x)= – 5x +4

The intercept is 4

Option C is the correct answer.

7 0

4 years ago

Use the common denominator to find -2/3 + -4/5

Svetlanka [38]

Answer:

-22/15

Step-by-step explanation:

Okay, so, find a common multiple of 3 and 5. best way to find one is to multiply them. 3 x 5= 15. Now you have to make the numerators equivalent.

-2/3 = -10/15

-4/5 = -12/15

-10+-12=-22

Answer:-22/15

5 0

3 years ago

Anybody help me to solve this question.

Mumz [18]

Answer:

$\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)} are\ in\ AP$

Step-by-step explanation:

Given that $(b-c)^2, (c-a)^2 , (a-b)^2$ are in AP

To prove: $\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)}$ are in AP

From given as we know if p , q, r are in AP then 2q= p+r.

$2(c-a)^2= (b-c)^2+(a-b)^2\\\\\Rightarrow 2(c^2+a^2-2ac)=b^2+c^2-2bc+a^2+b^2-2ab\\\\\Rightarrow 2c^2+2a^2-4ac= 2b^2+c^2+a^2 -2bc-2ab\\\\\Rightarrow a^2+c^2-2b^2-4ac= -2bc-2ab\\\\\Rightarrow a^2-2b^2+c^2= 4ac-2bc-2ab$

Now

$\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)}2\dfrac{1}{(c-a)} =\dfrac{1}{(b-c)}+\dfrac{1}{(a-b)}\\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-b+b-c}{(b-c)(a-b)} \\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-c}{(b-c)(a-b)} \\\\\Rightarrow2(b-c)(a-b) = (c-a)(a-c) \\\\\Rightarrow 2(ab-b^2-ac+bc)= -(a-c)^2\\\\\Rightarrow 2ab- 2b^2-2ac+2bc = -a^2-c^2+2ac\\\\\Rightarrow a^2-2b^2+c^2=4ac-2ab-2bc$

Which is the result of AP

Hence proved

6 0

3 years ago

Which number is irrational?

kobusy [5.1K]

I would go with A. 0.06 but I am not 100% sure.

8 0

3 years ago

Read 2 more answers