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just olya [345]
3 years ago
9

HELP PLEASEEEEEE I WILL GIVE YOU BRAINLIEST

Mathematics
1 answer:
Ivanshal [37]3 years ago
5 0

Answer:

Step-by-step explanation:

so brh

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Factor the polynomial completely using any method. Show steps.<br> 2d^4-13d^2-45
Alinara [238K]

Answer:

\huge ( {2d}^{2}  + 5)(d + 3)(d - 3)

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • factoring
  • PEMDAS
<h3>given:</h3>
  • 2d^4-13d^2-45
<h3>let's solve:</h3>

2d^4-13d^2-45

2 {d}^{4}  + 5 {d}^{2}  - 18 {d}^{2}  - 45 \\  {d}^{2} ( {2d}^{2}  + 5) - 9( {2d}^{2}  + 5) \\ ( {2d}^{2}  + 5)( {d}^{2}  - 9 )\\ ( {2d}^{2}  + 5)(d + 3)(d - 3)

3 0
3 years ago
The revenue, in dollars, of a company that produces video game systems can be modeled by the expression 5x2 + 2x – 80. The cost,
WINSTONCH [101]
<span>SALES:      5x² + 2x – 80
</span>- COST:      5x² – x + 100
=                 ------------------
PROFIT:      0x²+3x-180                        
(+3x because we subtracted a negative (-x), which is called adding, similarly taking away 100 from negative 80 is -180.)

Checking:
5x² + 2x – 80
5(500)²+2(500)-80 = 1,250,920

5x² – x + 100
5(500)² – (500) + 100= 1,249,600

Profit = 1,250,920 - 1,249,600 = 1,320
 
0(500)²+3(500)-180 = 1,320  YAY! {:-)

Double Checking:

5x² + 2x – 80
5(5000)²+2(5000)-80 = 125,009,920

5x² – x + 100
5(5000)² – (5000) + 100= 124,995,100

Profit = 125,009,920 - 124,995,100 = 14,820
 
0(5000)²+3(5000)-180 = <span>14,820</span>  YAY! {:-)



3 0
4 years ago
Read 2 more answers
If 4m=-15, then -12m=45 Name the property.​
Ainat [17]

Answer:

Communitave property

Step-by-step explanation:

8 0
3 years ago
Given MO is perpendicular to NP and NO is congruent to PO prove MN is congruent to MP
VladimirAG [237]
Lets imagine the shape 
M
  /\
  / | \
  / | \
  / | \
  P /___ |___\ N
  O
 Now in If we take â†MOP and â†MON
 As MO ⊥ NP so â MON=â MOP
 NO=NP (given)
 And MO is a common side 
 so by side angle side rule of congruency 
 â†MOP and â†MON are congruent
 so MP is congruent to MN
8 0
4 years ago
For which k are the roots of k(x2+1)=x2+3x–3 real and distinct?
Ugo [173]

Answer:

The solution for k is the interval (-3.5,1.5)

Step-by-step explanation:

we have

k(x^{2}+1)=x^{2}+3x-3

kx^{2}+k=x^{2}+3x-3

x^{2}-kx^{2}+3x-3-k=0

}[1-k]x^{2}+3x-(3+k)=0

we know that

If the discriminant is greater than zero . then the quadratic equation has two real and distinct solutions

The discriminant is equal to

D=b^{2}-4ac

In this problem we have

a=(1-k)

b=3

c=-(3+k)

substitute

D=3^{2}-4(1-k)(-3-k)\\ \\D=9-4(-3-k+3k+k^{2})\\ \\D=9+12+4k-12k-4k^{2}\\ \\D=21-8k-4k^{2}

so

21-8k-4k^{2} > 0

solve the quadratic equation by graphing

The solution for k is the interval (-3.5,1.5)

see the attached figure

7 0
3 years ago
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