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2 years ago

Is (4,2) a solution of the system y=x-2 and y=3x+4

Mathematics

2 answers:

Fed [463]2 years ago

5 0

Answer:

The answer to your question is No, it is not a solution

Step-by-step explanation:

Data

Point (4, 2)

y = x - 2 Equation l

y = 3x + 4 Equation ll

-Solve the system by equality

x - 2 = 3x + 4

-Solve for x

x - 3x = 4 + 2

- 2x = 6

-Result

x = 6/-2

x = -3

-Find y

y = -3 - 2

-Result

y = -5

The solution to this system is (-3, -5), (4,2) is not a solution.

babunello [35]2 years ago

4 0

Answer:

False

Step-by-step explanation:

y=x-2 y=3x+4

Substitute the point into both equations and see if it is true

2=4-2

2=2 true

and

2=3*4+4

2 = 12+4

2 =16

False

It is not a solution

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I need help with number 4

Tju [1.3M]

So you first want to move all variables to one side.

2x = 1/8 + 4x

So perform the opposite of each operation to move it.

2x - 4x = 1/8 + 4x - 4x

-2x = 1/8

And then just divide both sides by -2

-2x / -2 = 1/8 / -2

x = -1/16

8 0

3 years ago

9 times what number minus 7 equals negative seven

kirill115 [55]

9x-7=-7
9x=o
x=0
so the answer....is 0

8 0

3 years ago

Look at the graph shown below:

ElenaW [278]

So.. take a peek at the picture... let's get two points from it, hmm say 0,4 notice it touches the y-axis there, and say hmmm -4, 1, almost at the bottom of the line

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 0}}\quad ,&{{ 4}})\quad 
% (c,d)
&({{ -4}}\quad ,&{{ 1}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{1-4}{-4-0}$

$\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad 
\begin{array}{llll}
\textit{plug in the values for }
\begin{cases}
y_1=4\\
x_1=0\\
m=\boxed{?}
\end{cases}\\
\textit{and solve for "y"}
\end{array}\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}$

once you get the slope and solve for "y", that'd be the equation of the line.

7 0

2 years ago

What Val are restricted from the domain of

djverab [1.8K]

<u>Given</u>:

The given expression is $\frac{\left(4 x^{2}-4 x+1\right)}{(2 x-1)^{2}}$

We need to determine the values for which the domain is restricted.

<u>Restricted values:</u>

Let us determine the values restricted from the domain.

To determine the restricted values from the domain, let us set the denominator the function not equal to zero.

Thus, we have;

$(2x-1)^2\neq 0$

Taking square root on both sides, we get;

$2x-1\neq 0$

$2x\neq 1$

$x\neq \frac{1}{2}$

Thus, the restricted value from the domain is $x\neq \frac{1}{2}$

Hence, Option A is the correct answer.

7 0

3 years ago

For the function f(x)=3x, what is the translation for f(x)-2 and new function?

mario62 [17]

Answer:

A and E

Step-by-step explanation:

The translation f(x) - 2 means to subtract 3 from the whole function. As an equation this is 3x - 2. On the graph, the function will shift down vertically 2 units.

7 0

3 years ago