Answer:
-1,512,390
Step-by-step explanation:
Given
a1 = 15

Let us generate the first three terms of the sequence

For 

Hence the first three terms ae 15, 8, 1...
This sequence forms an arithmetic progression with;
first term a = 15
common difference d = 8 - 15 = - -8 = -7
n is the number of terms = 660 (since we are looking for the sum of the first 660 terms)
Using the formula;
![S_n = \frac{n}{2}[2a + (n-1)d]\\](https://tex.z-dn.net/?f=S_n%20%3D%20%5Cfrac%7Bn%7D%7B2%7D%5B2a%20%2B%20%28n-1%29d%5D%5C%5C)
Substitute the given values;
![S_{660} = \frac{660}{2}[2(15) + (660-1)(-7)]\\S_{660} = 330[30 + (659)(-7)]\\S_{660} = 330[30 -4613]\\S_{660} = 330[-4583]\\S_{660} = -1,512,390](https://tex.z-dn.net/?f=S_%7B660%7D%20%3D%20%5Cfrac%7B660%7D%7B2%7D%5B2%2815%29%20%2B%20%28660-1%29%28-7%29%5D%5C%5CS_%7B660%7D%20%3D%20330%5B30%20%2B%20%28659%29%28-7%29%5D%5C%5CS_%7B660%7D%20%3D%20330%5B30%20-4613%5D%5C%5CS_%7B660%7D%20%3D%20330%5B-4583%5D%5C%5CS_%7B660%7D%20%3D%20-1%2C512%2C390)
Hence the sum of the first 660 terms of the sequence is -1,512,390
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A unit rate is a special type of ratio (also called a single-unit rate). It will compare 1 unit of some quantity to a different number of units of a different quantity. Any ratio that is not a unit rate can be turned into one.
1) You will need to simplify both sides of the inequality.

2) Now you will need to subtract the like terms which leaves you with

We cannot do anything else so the answer will be
a<span>
ll real numbers are solutions.</span>
The bottom of the ladder is 10.5 feet away from the wall
Step-by-step explanation:
The given scenario forms a right triangle.
Where
The length of ladder will be the hypotenuse
The wall on which the window is situated will ebt he perpendicular and
The distance between the foot of ladder and the wall will be the base
So,
Hypotenuse = H = 20 foot
Perpendicular = P = 17 feet
Base = B = ?
Using the Pythagoras theorem

The bottom of the ladder is 10.5 feet away from the wall
Keywords: Triangle, Pythagoras Theorem
Learn more about Pythagoras theorem at:
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