All categories

2 years ago

Find the angle between the given vectors to the nearest degree.

Mathematics

2 answers:

konstantin123 [22]2 years ago

6 0

Answer:

c. 108.4

Step-by-step explanation:

cos theta = (u dot v)/ (||u|| ||v||)

where dot stands for dot product and || || is the magnitude

u = (1,5) v= (7,-4)

u dot v = (1*7 + 5*-4) = 7-20 = -13

||u|| = sqrt( 1^2 +5^2) = sqrt(1+25) = sqrt(26)

||v|| = sqrt(7^2 + (-4)^2) = sqrt(49+16) = sqrt(65)

cos theta = -13/ sqrt(26) sqrt(65)

cos theta = -13 /sqrt(1690)

theta = arccos (-13/sqrt(1690))

theta = 108.43

VLD [36.1K]2 years ago

3 0

I believe the answer is c

You might be interested in

Question 5 (12 points)

Dima020 [189]

Answer:

see attached for diagram

a) √13

b) √29

c) 4

Step-by-step explanation:

Equation of the circle: $(x + 1)^2 + (y - 3)^2 = 16$

⇒ center = (-1, 3)

⇒ radius = √16 = 4

Distance between 2 points formula:

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

a) let (-1, 3) = $(x_1,y_1)$

let (2, 1) = $(x_2, y_2)$

$\implies \sqrt{(2+1)^2+(1-3)^2} =\sqrt{13}$

b) let (-1, 3) = $(x_1,y_1)$

let (4, 1) = $(x_2, y_2)$

$\implies \sqrt{(4+1)^2+(1-3)^2} =\sqrt{29}$

c) let (-1, 3) = $(x_1,y_1)$

let (3, 3) = $(x_2, y_2)$

$\implies \sqrt{(3+1)^2+(3-3)^2} =4$

4 0

1 year ago

Read 2 more answers

Factors and common factors of 24,64,88

babunello [35]

24- 1,2,3,4,6,8,12,24
64-1,2,4,8,16,32,64
88-1,2,4,8,11,22,44,88

Here are all the factors.^^
The common factors are 1,2,3,4,6
Hope this helps!

8 0

2 years ago

Helppp! Again! Please!!

erastovalidia [21]

Answer:

pretty sure its 6, i think

6 0

2 years ago

PLS HELP WITH THIS MATH

laiz [17]

I think it’s 28.35

54/100 x 5 = 2.7
54 + 2.7 = 56.7
56.7/100 x 50 = 28.35
56.7 -28.35 = 28.35

6 0

2 years ago

Read 2 more answers

1. Graph each point on the imaginary plane. The first number x is along thehorizontal axis, referred to as the real axis. The se

AlekseyPX

$z=3-4i$

$z=-5-2i$ $z=4+3i$ $z=-2+4i$

4 0

3 months ago