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3 years ago

Simplifying algebraic expressions -8-4m-4m-8+ -3+10m

Mathematics

1 answer:

marissa [1.9K]3 years ago

6 0

-2m-9 is the simplified expression

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A boundary stripe 6 in. wide is painted around a rectangle whose dimensions are 120 ft by 230 ft. Use differentials to approxima

Nimfa-mama [501]

Answer:

350 square feet

Step-by-step explanation:

We are given that

Width of strip=6 in

Dimension of rectangle= $20 ft\times 230 ft$

We know that

Area of rectangle ,A=xy

Differentiate

$dA=\frac{\partial A}{\partial x}x+\frac{\partial A}{\partial y}y$

We have $\frac{\partial A}{\partial x}=y=230 ft$

$\frac{\partial A}{\partial y}=x=120$

$dx=\frac{12}{12}=1 ft$

1 ft=12 in

Because 6 in added in both side of breadth

dy= $\frac{12}{12}=1 ft$

Because 6 in added on both sides of length of rectangle

Substitute the values

$dA=230\times 1+120\times 1=350 ft^2$

Hence, the number of square feet of paint in the strip=350 square feet

7 0

3 years ago

Help me with this please someone help!!!

Ber [7]

There's a 40% chance that the next cereal box will contain a blue or yellow ring.

4 0

3 years ago

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The lengths of two sides of a right triangle are given. Find the length of the third side. Round to the nearest tenth if necessa

ivann1987 [24]

Answer:

Explanation

$\sqrt{a^{2} b ^{2} }$

$\sqrt{28^{2}15 ^{2} }$

c= 31.76476

c= 32inch

7 0

2 years ago

Write a system of two linear equations showing the distance each animal can

Oksana_A [137]

Answer:

Lion: y = 50x - 295

Elephant: y = 25x - 147.5

Step-by-step explanation:

3 0

2 years ago

The graph of f(x) consists of 14 points. Six of the points lie in Quadrant I of the coordinate plane. If f(x) is an odd function

xz_007 [3.2K]

If f(x) is an odd function, the greatest number of points that can lie in Quadrant II is 1

<h3>How to determine the number of points?</h3>

The given parameters are:

Function f(x) = Odd function

Points in quadrant IV

The number of points in the upper quadrants is:

Upper = 14/2

This gives

Upper = 7

The upper quadrants are I and II

This means that:

I + II = 7

So, we have:

6 + II = 7

Subtract 6 from both sides

II = 1

Hence, the greatest number of points that can lie in Quadrant II is 1