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3 years ago

Determine the slope (8grade

Mathematics

1 answer:

coldgirl [10]3 years ago

4 0

Answer: 1/2

Step-by-step explanation: I believe the answer is 1/2 because for (2,-6) and (4,-7) the rise over run is 1/2. I don't know though

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I need help with this does anyone understand this?

soldier1979 [14.2K]

Answer:

Let y = f(x)

$= > y = \frac{19}{ {x}^{3} }$

$= > {x}^{3} = \frac{19}{y}$

$= > x = \sqrt[ 3]{ \frac{19}{y} }$

${f}^{ - 1} (x) = \frac{ \sqrt[3]{19} }{ \sqrt[3]{x} }$

<h2>option A</h2>

4 0

3 years ago

Twelve subtracted from twelve times a number is 240. What is the number?

vovangra [49]

Answer:

Step-by-step explanation:

Let x = the number

12x-12 = 240

12x = 252

x = 21

5 0

3 years ago

Triangle ABC is translated using the rule (x, y) → (x + 1, y − 4) to create triangle A′B′C′. If a line segment is drawn from poi

nalin [4]

Answer:

The line segments AA' and BB' are parallel and congruent

Step-by-step explanation:

4 0

3 years ago

PLEASE HELP IF YOU ARE GOOD AT ALGEBRA 2 MATH

REY [17]

Answer:I think a is:78.3 since it would be the same and since 0 doesn't have a value.

I think b is: 139.5 because all you are doing is subtracting 287.1-147.6

7 0

3 years ago

Given the functionf ( x ) = x^2 + 7 x + 10/ x^2 + 9 x + 20

vladimir1956 [14]

<em>x = -4 is a vertical asymptote for the function.</em>

<h2>Explanation:</h2>

The graph of $y=f(x)$ is a vertical has an asymptote at $x=a$ if at least one of the following statements is true:

$1) \ \underset{x\rightarrow a^{-}}{lim}f(x)=\infty\\ \\ 2) \ \underset{x\rightarrow a^{-}}{lim}f(x)=-\infty \\ \\ 3) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty \\ \\ 4) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty$

The function is:

$f(x)=\frac{x^2+7x+10}{x^2+9x+20}$

First of all, let't factor out:

$f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20} \\ \\ f(x)=\frac{x(x+5)+2(x+5)}{x(x+5)+4(x+5)} \\ \\ f(x)=\frac{(x+5)(x+2)}{(x+5)(x+4)} \\ \\ f(x)=\frac{(x+2)}{(x+4)}, \ x\neq 5$

From here:

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ right: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(-4^{+}+2)}{(-4^{+}+4)} \\ \\ \\ The \ numerator \ is \ negative \ and \ the \ denominator \\ is \ a \ small \ positive \ number. \ So: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=-\infty$

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ left: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(-4^{-}+2)}{(-4^{-}+4)} \\ \\ \\ The \ numerator \ is \ a \ negative \ and \ the \ denominator \\ is \ a \ small \ negative \ number \ too. \ So: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=+\infty$

Accordingly:

$x=-4 \ is \ a \ vertical \ asymptote \ for \\ \\ f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20}$

<h2>Learn more:</h2>

Vertical and horizontal asymptotes: brainly.com/question/10254973

#LearnWithBrainly

5 0

3 years ago