Answer:

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
Step-by-step explanation:
Normal with mean 6.88 minutes and
a standard deviation of 0.57 minutes.
Choose a student at random from this group and call his time for the mile Y. Find P(Y<6)


y ≈ normal (μ, σ)
The z score is the value decreased by the mean divided by the standard deviation

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
I have nooo clue the problem doesn’t make sense
Answer:
a=2;b=4;c=6.
Louis wrote the correct answer.
So (m+n)/2= 7
To find m+n, multiply both sides by 2
m+n=14
Final answer: C