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3 years ago

What is 5/8 times 7/9?

Mathematics

2 answers:

Vladimir79 [104]3 years ago

8 0

35/72. Multiply numerators and then multiply denominators then simplify. :)

12345 [234]3 years ago

8 0

35/72. I divide. 0.486111111111111

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4(2x + 3) ÷ 5y From the expression above, provide an example of each of the following: sum, term, product, factor, quotient, and

Ann [662]

Answer:

Sum - 2x + 3

term - 2x

Product - 4(2x + 3)

Factor - not present

quotient - (2x + 3) / 5

Coeffecient - 4(2x + 3)

I really hope this helps

6 0

3 years ago

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Dylan has a roll of wrapping paper that is5 meters long. How many centimeters of wrapping paper does he have.

In-s [12.5K]

500 centimeters I think *sweats nervously*

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2 years ago

Plz Plz help its hard

Katena32 [7]

Answer:

Third answer! Data varies!

3 0

2 years ago

The circle with center O has a minor arc BSA with a length of

tangare [24]

Answer:

D. $\frac{27\pi}{2}$ inches.

Step-by-step explanation:

We have been given that the circle with center O has a minor arc BSA with a length of $3\pi^{2}$ inches. The central angle is 40°.

To find the circumference of circle we will use formula:

$\frac{\text{Central angle}}{2\pi}=\frac{\text{Arc length}}{2\pi r}$ , where $2\pi$ = measure of 360 degrees in radians and $2\pi r$ = circumference of circle.

Let us convert measure of central angle into radians.

$40^{o}=\frac{40*\pi}{180} =\frac{2\pi}{9}$

Upon substituting our given value in the formula we will get,

$\frac{\frac{2\pi}{9}}{2\pi}=\frac{\frac{3\pi}{2}}{2\pi r}$

$\frac{2\pi}{18\pi}=\frac{3\pi}{4\pi r}$

$\frac{1}{9}=\frac{3}{4r}$

Cross multiplying we will get,

$4r=27$

$r=\frac{27}{4}$

Hence, the radius of our circle is 27/4 inches.

Since the circumference of circle is $2\pi r$ . Upon substituting $r=\frac{27}{4}$ we will get,

$2\pi r=2\pi* \frac{27}{4}=\frac{27\pi}{2}$

Therefore, circumference of our given circle will be $\frac{27\pi}{2}$ inches and option D is the correct choice.

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2 years ago

Name the postulate or theorem you can use to prove

gladu [14]

AAS

A for <SUR and <TVR

A for <SRU and <TRV

S for SU and TV

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2 years ago

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