A probability experiment will consist of selecting one student at random from your math class. Is the probability that the selec
ted student is female greater than, equal to,or less than the probability that the selected student is male? Explain your reasoning
1 answer:
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Well let's say that to compare these two numbers, we have to start with the definition first.
<u>D</u><u>e</u><u>f</u><u>i</u><u>n</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u>
Looks like we can use any x-values right? Nope.
The value of x only applies to any positive real numbers for one reason.
As we know, any numbers time itself will result in positive. No matter the negative or positive.
<u>D</u><u>e</u><u>f</u><u>i</u><u>n</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>I</u><u>I</u>
Where b is the result from a×a. Let's see an example.
<u>E</u><u>x</u><u>a</u><u>m</u><u>p</u><u>l</u><u>e</u><u>s</u>
So basically, their counterpart or opposite still gives same value.
Then you may have a question, where does √-1 come from?
It comes from this equation:
When we solve the quadratic equation in this like form, we square both sides to get rid of the square.
Then where does plus-minus come from? It comes from one of Absolute Value propety.
<u>A</u><u>b</u><u>s</u><u>o</u><u>l</u><u>u</u><u>t</u><u>e</u><u> </u><u>V</u><u>a</u><u>l</u><u>u</u><u>e</u><u> </u><u>P</u><u>r</u><u>o</u><u>p</u><u>e</u><u>r</u><u>t</u><u>y</u><u> </u><u>I</u>
Solving absolute value always gives the plus-minus. Therefore...
Then we have the square root of -1 in negative and positive. But something is not right.
As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.
Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.
Then we have another number which is -√1. This one is simple.
It is one of the solution from the equation y^2 = 1.
We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.
<u>C</u><u>o</u><u>n</u><u>c</u><u>l</u><u>u</u><u>s</u><u>i</u><u>o</u><u>n</u>
So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.