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Alecsey [184]
3 years ago
12

What is the value of ƒ(– 6) when ƒ(x) = x2 + 8x + 10?

Mathematics
1 answer:
marishachu [46]3 years ago
5 0
f(x)= x^{2} +8x+10
f(-6) = (-6)^2+8(-6)+10
f(-6)=36-48+10 = -2
f(-6)=-2
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