Answer:
The Upper Bound of the 99% confidence interval about the mean number of orcs per raiding party is of 106.83 orcs per party.
Step-by-step explanation:
We have the standard deviation of the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 13 - 1 = 12
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 12 degrees of freedom(y-axis) and a confidence level of
. So we have T = 3.0545
The margin of error is:
M = T*s = 3.0545*7.8 = 23.83
In which s is the standard deviation of the sample.
The upper end of the interval is the sample mean added to M. So it is 83 + 23.83 = 106.83 orcs per party.
The Upper Bound of the 99% confidence interval about the mean number of orcs per raiding party is of 106.83 orcs per party.
This is a "rate of pay" problem. The amount earned is equal to the (rate of pay) times the (number of hours worked).
Let the income be represented by "i". Then the formula is i = ($10.91/hour)*w, where w is the number of hours worked and has the unit of measurement "hours."
The simplified probability would be 12/91.
There are 4 green jelly beans out of a total of 14 jelly beans. The probability for the first bean would be 4/14.
Once the first jelly bean is removed, the probability that the second jelly bean would be red is 6/13 (the denominator decreases by 1 because of the first jelly bean that did not get put back).
Together the probability is (4/14)(6/13) = 24/182, which then simplifies to 12/91.
The quotient is 2x^2-5x+2
Answer:
C
Step-by-step explanation: