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kompoz [17]
3 years ago
13

Someone please help me on this!!! It’s due right now

Mathematics
1 answer:
kirza4 [7]3 years ago
3 0

Answer:

range = {-8,-5,-2,1}

Step-by-step explanation:

you can plug in each value for x.

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Write an equation in slope-intercept form of the line with the given slope m and y-intercept b.
Paul [167]

Answer:

y=-4x+7/2

Step-by-step explanation:

slope-intercept form follows the following format:

y=mx+b

simply replace m with -4 and b with 7/2

7 0
3 years ago
Given: f(x) = 2x-1 and g(x) = 2x-3<br> Find:<br> (fog)(x)<br> HELP PLEASEE!!
Murljashka [212]

Answer:

(fog)(x) = 4x - 7

Step-by-step explanation:

f(x) = 2x-1 and g(x) = 2x-3;

(fog)(x) = f(g(x)

= f(2x - 3) = 2(2x - 3) - 1

= 4x - 6 - 1

= 4x - 7

7 0
3 years ago
What is the area of a circle with a radius of 1 foot?<br> *Ht2<br> 2***<br> seft<br> 2 x ft?
Svetach [21]

Answer:

pi

Step-by-step explanation:

5 0
3 years ago
Would appreciate the help 24 points
andre [41]

Answer:

13) Rectangle

14) parallelogram

15) co ordinates areD (0,a) andE (c,b)

16) co ordinates are D(0,b) and E(a,0)

17)(-1,1) (4,1) (-1,4)

18)(0,0) (a,0) (a,a) (0,a)

Step-by-step explanation:

<h3>13)</h3><h3>Rectangle</h3>

The opposite sides of a rectangle are parallel and equal

left height = right height

(by using distance formula)

(0,3),(2,-2) = (5,5),(7,0)

√(2-0)²+(-2-3)² = √(7-5)²+(0-5)²

√(2)²+(-5)² = √(2)²+(-5)²

√4+25 = √(2)²+(-5)²

√29 = √29 hence equal

<h3>14)</h3><h3>parallelogram</h3>

The opposite sides of a rectangle are not equal

left height = right height

(by using distance formula)

(0,0),(3,-4) = (3,4),(7,0)

√(3-0)²+(-4-0)² = √(7-3)²+(0-4)²

√(3)²+(-4)² = √(5)²+(-4)²

√9+16 = √(25)+(16)

√(25) ≠√41

5 ≠ √41

<h3>15)</h3><h3>co ordinates are D(0,a) and E(c,b)</h3><h3>16)</h3><h3>co ordinates are D(0,b) and E(a,0) </h3>

since rhombus have equal opposite sides

<h3>17)</h3><h3>(-1,1) (4,1) (-1,4)</h3><h3>18)</h3><h3>(0,0) (a,0) (a,a) (0,a)</h3><h3 />

6 0
3 years ago
If a quadratic function has x-intercepts at 2 = -
PolarNik [594]

Complete question is;

If a quadratic function has x-intercepts at x = -3 and x = -1, one possible equation of the function would be y = (x + 3)(x + 1), a graph that first

decreases until it reaches the vertex, (-3, -1), then increases (opening upward U shape).

So then, if a quadratic function has x-intercepts at x = -2 and x = 2

a. What is the equation of this quadratic function? Explain your reasoning

b. What is the vertex of the equation? Show your work and explain your reasoning.

Answer:

Quadratic equation is; y = x² - 4

Vertex: (0, -4)

Step-by-step explanation:

The x-intercepts are at x = -2 and x = 2. Thus, the equation is;

y = (x - (-2))(x - 2)

y = x² + 2x - 2x - 4

y = x² - 4

Now,the coordinates of the vertex will be (h, k)

Where;

h = -b/2a

k is the value of y at x = h

From y = x² - 4, h = 0

Thus, putting x = h = 0 in the quadratic equation, we have;

y = 0² - 4

y = -4

Thus,the coordinates of the vertex are; (0, -4)

3 0
3 years ago
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