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frosja888 [35]
3 years ago
12

How many solutions does the following equation have? -3u=-3u-10

Mathematics
1 answer:
olga2289 [7]3 years ago
3 0

Answer:

There are no solutions

Step-by-step explanation:

-3u=-3u-10

Add 3u to each side

-3u+3u=-3u+3u-10

0 = -10

This is never true so there are no solutions

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Help with these please.
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For numbers 15-17, we need to remember that two of a triangle's angles are always acute and the third angle will allow us to classify the triangle based on its angles. now that we know this, let's look at #15. the first two angles listed are acute, and the third is an obtuse angle, therefore it is an obtuse triangle. on #16 we have three acute angles, so it is an acute triangle. #17 has two acute angles and a right angle so it is a right triangle.
on numbers 21-23, we need to know that a triangle with all congruent sides is called equilateral, a triangle with two equal sides is isosceles, and a triangle with no equal sides is called scalene. #21 shows two equal sides so it is an isosceles triangle. #22 has three equal sides so it is an equilateral triangle. #23 has no equal sides so it is scalene. hope this helped! :)
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3 years ago
Please help me!! i have no clue what i am doing on this one.
Sonja [21]

Answer:

yr answer is G. 21

<h2>stay safe healthy and happy<u>.</u><u>.</u></h2>

8 0
3 years ago
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PLEASE HELP! WILL AWARD BRAINLIEST TO THE FIRST CORRECT ANSWER!
Ahat [919]

Answer:

E) 6

Step-by-step explanation:

a/b = 6

36/b = 6

6b = 36

b = 36/6 = 6

b/x = 36

6/x = 36

36x = 6

x = 6/36 = 1/6

hence 1/x = 6

3 0
2 years ago
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Find the exact value of sin(cos^-1(4/5))
boyakko [2]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2762144

_______________


Let  \mathsf{\theta=cos^{-1}\!\left(\dfrac{4}{5}\right).}


\mathsf{0\le \theta\le\pi,}  because that is the range of the inverse cosine funcition.


Also,

\mathsf{cos\,\theta=cos\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]}\\\\\\&#10;\mathsf{cos\,\theta=\dfrac{4}{5}}\\\\\\ \mathsf{5\,cos\,\theta=4}


Square both sides and apply the fundamental trigonometric identity:

\mathsf{(5\,cos\,\theta)^2=4^2}\\\\&#10;\mathsf{5^2\,cos^2\,\theta=4^2}\\\\&#10;\mathsf{25\,cos^2\,\theta=16\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\&#10;\mathsf{25\cdot (1-sin^2\,\theta)=16}

\mathsf{25-25\,sin^2\,\theta=16}\\\\&#10;\mathsf{25-16=25\,sin^2\,\theta}\\\\&#10;\mathsf{9=25\,sin^2\,\theta}\\\\&#10;\mathsf{sin^2\,\theta=\dfrac{9}{25}}&#10;

\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{9}{25}}}\\\\\\&#10;\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{3^2}{5^2}}}\\\\\\&#10;\mathsf{sin\,\theta=\pm\,\dfrac{3}{5}}


But \mathsf{0\le \theta\le\pi,} which means \theta lies either in the 1st or the 2nd quadrant. So \mathsf{sin\,\theta} is a positive number:

\mathsf{sin\,\theta=\dfrac{3}{5}}\\\\\\&#10;\therefore~~\mathsf{sin\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]=\dfrac{3}{5}\qquad\quad\checkmark}


I hope this helps. =)


Tags:  <em>inverse trigonometric function cosine sine cos sin trig trigonometry</em>

3 0
3 years ago
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3) Two cars leave Cincinnati at the same time. Car A moves East at a constant speed of 60 miles per hour, while car B
Inessa [10]

Answer:

D). 262.5 miles.

Step-by-step explanation:

The speed at which they are drawing apart = 60 + 45 = 105 mph.

So in 2.5 hours they wiil be

2.5 * 105

= 210 + 52.5

= 262.5 miles.

4 0
2 years ago
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