How do you do question 6
1 answer:
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Answer:
h(x) = -16x² + 192x + 208
784ft
6 sec
13 sec
Step-by-step explanation:
a)
h(x) = -16x² +vx + h
here v represent velocity
represent initial height of launch
h(x) = -16x² + 192x + 208
b)
h(x) = -16x² + 192x + 208
here a = -16
b = 192
c = 208
x = -b/2a
= -192/2(-16)
= 6
plug this value in the equation
h(x) = -16(6)² + 192(6) + 208
= 784ft
e)
Plug h(x)=0 in the equation
0 = -16x² + 192x + 208
divide equation by -16
x² - 12x - 13 = 0
Factors
1x * -13x = -13
1x - 13x = -12
Factorised form
x² - 12x - 13 = 0
x² + x - 13x - 13 = 0
x(x+1) -13(x+1) = 0
(x+1)(x-13) = 0
x = -1
x = 13
Since time can not be negative so we will reject x = -1
<u>Given</u>:
Given that ABCD is a rectangle.
The diagonals of the rectangle are AC and DB.
The length of AE is (6x -55)
The length of EC is (3x - 16)
We need to determine the length of the diagonal DB.
<u>Value of x:</u>
The value of x can be determined by equating AE and EC
Thus, we have;
Substituting the values, we get;
Thus, the value of x is 13.
<u>Length of AC:</u>
Length of AE =
Length of EC =
Thus, the length of AC can be determined by adding the lengths of AE and EC.
Thus, we have;
Thus, the length of AC is 46.
<u>Length of DB:</u>
Since, the diagonals AC and DB are perpendicular to each other, then their lengths are congruent.
Hence, we have;
Thus, the length of DB is 46.