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PtichkaEL [24]
3 years ago
5

Look at the figure below. Which of the following statements could be a step in a proof that vertical

Mathematics
1 answer:
Svetach [21]3 years ago
6 0

Answer: B

Step-by-step explanation:

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Please solve this question asap
disa [49]

Step-by-step explanation:

y =  \sqrt{4x + 6}

{y}^{2}  = 4x + 6

{y}^{2}  - 6 = 4x

\frac{1}{4} ( {y}^{2}  - 6) = x

Swap x and y

\frac{ {x}^{2} - 6 }{4}  = y

3 0
2 years ago
The ratio of orange crayons to purple crayons is 2/4if there are 64 orange crayons the box how many purple crayons are there in
lesya692 [45]

2/4=1/2 two is 2 times greater than one so what is two times greater that 64?

64x2=128

6 0
3 years ago
Read 2 more answers
rocky reifenstuhl won the 130-mile race on his bicycle. he finished in 11 hours and 45 minutes. What was his average speed in mi
Marat540 [252]

R=D/T

130 = r x 11.75

R=130/11.75=11.06

11.06 MPH



8 0
3 years ago
The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co
Alona [7]

Answer:

95% Confidence interval for the variance:

3.6511\leq \sigma^2\leq 34.5972

95% Confidence interval for the standard deviation:

1.9108\leq \sigma \leq 5.8819

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

s^2=2.89^2=8.3521

The confidence interval for the variance is:

\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128

Then, the confidence interval can be calculated as:

\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819

6 0
3 years ago
Growth or decay, and determine the percentage rate of increase or decrease.
NNADVOKAT [17]

The expression y = 660(0.902)ˣ represents a decay , the rate of decrease is 9.8% .

In the question ,

it is given that ,

the the exponential function is y = 660(0.902)ˣ

we need to determine that , the equation represents a growth or decay .

0.902 is the variable that will determine a growth or decay .

Since, 0.902 is less than 1 , so it represents a decay function .


To find the rate we subtract 0.902 from 1

= 1 - 0.902

= 0.098

= 9.8% decrease rate

Therefore , The expression y = 660(0.902)ˣ represents a decay , the rate of decrease is 9.8% .

The given question is incomplete , the complete question is

Identify if it's Growth or Decay , and determine the percentage rate of increase or decrease , the function is y = 660(0.902)ˣ ?

Learn more about Growth and Decay here

brainly.com/question/22392518

#SPJ1

4 0
1 year ago
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