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yawa3891 [41]
3 years ago
12

If a bag contains 6 red balls, 4 green balls, and 3 blue balls. If we choose a ball, then another ball without putting the first

one in the bag, what is the probability that the first ball is green anda the second one red
Mathematics
1 answer:
Evgesh-ka [11]3 years ago
8 0

hello,

red 6

green 4

blue 3

  • first ball is green:

\frac{4}{13}

  • second ball is red:

\frac{6}{12}  =  \frac{1}{2}

The probability that these two events happen at the same time is:

\frac{4}{13}  \times  \frac{1}{2}  =  \frac{4}{26}  =  \frac{2}{13}

\boxed{crsjr}

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