What is the solution to the system of equations below? HELP!!!! y = negative one-fourth x + 2 and 3 y = negative three-fourths x
minus 6 no solution infinitely many solutions (–16, 6) (–16, –2)
2 answers:
Answer:
No solution
Step-by-step explanation:
Step 1: Write out equations
y = -1/4x + 2
3y = -3/4x - 6
Step 2: Substitution
3(-1/4x + 2) = -3/4x - 6
Step 3: Distribute
-3/4x + 6 = -3/4x - 6
From here, we can see that we have the same slope but different y-intercept. This means that the 2 lines are parallel and therefore never intersect.
Alternatively, you could graph the equations and see that the 2 lines are parallel and never intersect.
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Answer:
y = x -
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = - 4x + 38 is in this form with slope m = - 4
The line ST is perpendicular to line RS ( angles in a square are 90° )
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
=
y = x + c ← is the partial equation
To find c substitute (2, - 4) into the partial equation
- 4 = + c ⇒ c = - 4 -
= -
y = x -
← equation of ST