What is the solution to the system of equations below? HELP!!!! y = negative one-fourth x + 2 and 3 y = negative three-fourths x
minus 6 no solution infinitely many solutions (–16, 6) (–16, –2)
2 answers:
Answer:
No solution
Step-by-step explanation:
Step 1: Write out equations
y = -1/4x + 2
3y = -3/4x - 6
Step 2: Substitution
3(-1/4x + 2) = -3/4x - 6
Step 3: Distribute
-3/4x + 6 = -3/4x - 6
From here, we can see that we have the same slope but different y-intercept. This means that the 2 lines are parallel and therefore never intersect.
Alternatively, you could graph the equations and see that the 2 lines are parallel and never intersect.
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Answer:
- distance to x-axis: 3 units
- distance to y-axis: 2 units
- the reflected point is (2, 3)
Step-by-step explanation:
The given point is (-2, 3), labeled point A in the attachment.
As you know, the distance from the x-axis is given by the y-coordinate. Here, that distance is ...
3 units from the x-axis
__
The distance from the y-axis is given by the magnitude of the x-coordinate. Here, that distance is ...
2 units from the y-axis
Note that the negative coordinate value means the point is located that distance to the left of the y-axis.
__
Reflecting the point across the y-axis means choosing a point that is the same distance (2 units) right of the axis instead of left of the axis. The sign of the x-coordinate value will be positive, instead of negative. (The y-coordinate remains unchanged,)
__
The reflected point is (2, 3).
_____
<em>Additional comment</em>
As we have seen, reflection across the y-axis changes the sign of the x-coordinate:
(x, y) ⇒ (-x, y) . . . . reflection across the y-axis
Similarly, reflection across the x-axis changes the sigh of the y-coordinate:
(x, y) ⇒ (x, -y) . . . . reflection across the x-axis
