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Maslowich
3 years ago
13

What is the solution to the system of equations below? HELP!!!! y = negative one-fourth x + 2 and 3 y = negative three-fourths x

minus 6 no solution infinitely many solutions (–16, 6) (–16, –2)

Mathematics
2 answers:
Oxana [17]3 years ago
5 0

Answer:

No solution

Step-by-step explanation:

Step 1: Write out equations

y = -1/4x + 2

3y = -3/4x - 6

Step 2: Substitution

3(-1/4x + 2) = -3/4x - 6

Step 3: Distribute

-3/4x + 6 = -3/4x - 6

From here, we can see that we have the same slope but different y-intercept. This means that the 2 lines are parallel and therefore never intersect.

Alternatively, you could graph the equations and see that the 2 lines are parallel and never intersect.

Goryan [66]3 years ago
4 0

Answer:

No solution

Step-by-step explanation:

y = -1/4x + 2

3y = -3/4x - 6

Plug y as -1/4x + 2 in the second equation.

3(-1/4x + 2) = -3/4x - 6

-3/4x + 6 = -3/4x - 6

-3/4x + 3/4x = -6 -6

0 = -12

No solution.

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I need help solving this problem.
Galina-37 [17]

Answer:

y = \frac{1}{4} x - \frac{9}{2}

Step-by-step explanation:

The equation of a line in slope- intercept form is

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The line ST is perpendicular to line RS ( angles in a square are 90° )

Given a line with slope m then the slope of a line perpendicular to it is

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y = \frac{1}{4} x - \frac{9}{2} ← equation of ST


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