What is the solution to the system of equations below? HELP!!!! y = negative one-fourth x + 2 and 3 y = negative three-fourths x
minus 6 no solution infinitely many solutions (–16, 6) (–16, –2)
2 answers:
Answer:
No solution
Step-by-step explanation:
Step 1: Write out equations
y = -1/4x + 2
3y = -3/4x - 6
Step 2: Substitution
3(-1/4x + 2) = -3/4x - 6
Step 3: Distribute
-3/4x + 6 = -3/4x - 6
From here, we can see that we have the same slope but different y-intercept. This means that the 2 lines are parallel and therefore never intersect.
Alternatively, you could graph the equations and see that the 2 lines are parallel and never intersect.
Answer:
No solution
Step-by-step explanation:
y = -1/4x + 2
3y = -3/4x - 6
Plug y as -1/4x + 2 in the second equation.
3(-1/4x + 2) = -3/4x - 6
-3/4x + 6 = -3/4x - 6
-3/4x + 3/4x = -6 -6
0 = -12
No solution.
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It’s, 4+x=12. Hope this helps☺️
This could be written as y= -2x+6 in standard form
Since <span> sin(α) > 0 and cos(α) > 0
so </span><span>α is IN THE FIRST QUADRANT (I)</span>
<span>−4.0 is an integer.
hope it helps</span>
Answer:
Step-by-step explanation:
With replacement
(1/10)^4
1/10000
0.0001
Without replacement
(1/10)(1/9)(1/8)(1/7)
1/5040
0.00019841269