Answer:
21
Step-by-step explanation:
I did the math.
The answer would be number 1. 173 units^2
Answer:
7 1/17
Step-by-step explanation:
A figure can be helpful.
The inscribed semicircle has its center at the midpoint of th base. It is tangent to the side of the isosceles triangle, so a radius makes a 90° angle there.
The long side of the isosceles triangle can be found from the Pythagorean theorem to be ...
BC² = BD² +CD²
BC² = 8² +15² = 289
BC = √289 = 17
The radius mentioned (DE) creates right triangles that are similar to ∆BCD. In particular, we have ...
(long side)/(hypotenuse) = DE/BD = CD/BC
DE = BD·CD/BC = 8·15/17
DE = 7 1/17 ≈ 7.059
Answer:
Answer: The percentage increase is 78.68%
Step-by-step explanation:
Complete Question
When the Olympic Games were held outside Mexico City in 1968, there was much discussion about the effect the high altitude (7340 feet) would have on the athletes. Assuming air pressure decays exponentially by 0.5% every 100 feet, by what percentage is air pressure reduced by moving from sea level to Mexico City?
Round your answer to one decimal place.
....... %
Answer:
The value is
Step-by-step explanation:
From the question we are told that
The height of Mexico city is h = 7340 feet
The rate at which air pressure decays is 0.5% per 100 feet
From the data given
=>
=>