Answer:
a) 
b) 
c) 
With a frequency of 4
d) 
<u>e)</u>
And we can find the limits without any outliers using two deviations from the mean and we got:

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case
Step-by-step explanation:
We have the following data set given:
49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000
Part a
The mean can be calculated with this formula:

Replacing we got:

Part b
Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

Part c
The mode is the most repeated value in the sample and for this case is:

With a frequency of 4
Part d
The midrange for this case is defined as:

Part e
For this case we can calculate the deviation given by:

And replacing we got:

And we can find the limits without any outliers using two deviations from the mean and we got:

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case
Answer:
1 Chair= $1.25 1 table= $8.25
Step-by-step explanation:
5c+3t=31
2c+6t= 52
-2(5c+3t=31)
-10c-6t=-62
+
2c+6t=52
= -8c=-10
/-8 /-8
c= 1.25 or 1 1/4
2c+6t=52
2(1.25)+6t=52
2.5+6t=52
-2.5 -2.5
6t= 49.5
/6 /6
t= 8 1/4
-4 is greater than - 10 because -4 is closer to 0 than -10 is
Answer:
by using Pythagoras law
h²=p²+b²
13²=9²+b²
169-81=b²
b=√88=2√22m is your answer