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vagabundo [1.1K]
3 years ago
5

How do you write 12 divided by 90 as a product

Mathematics
2 answers:
shutvik [7]3 years ago
3 0
12/90 = 0.13 is the answer I believe
insens350 [35]3 years ago
3 0
12/90 = 0.13 <---- Answer
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Find the slope using the formula.<br> (3,-2) and (3, 6)
dangina [55]

Answer:

m = undef

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

  • Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (3, -2)

Point (3, 6)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{6+2}{3-3}
  2. Add/Subtract:               m=\frac{8}{0}
  3. Divide:                          m = undef

When we divide anything by zero, we will get undefined. Therefore, this would be a vertical line.

6 0
3 years ago
Find the area of the following<br> trapezoid:<br> 8 cm<br> 5 cm<br> 4 cm<br> 16 cm<br> A = [?] cm2
11111nata11111 [884]
My bad i used S instead of A so just switch the letter. hope this helps tho have a nice day

5 0
3 years ago
Read 2 more answers
Find the point on the terminal side of θ = 3pi/4 that has a y coordinate of 1. Show your work for full credit.
bagirrra123 [75]
Ok, we know the angle is 3π/4, and that y-coordinate is 1, hmm what's "x"?

\bf tan(\theta)=\cfrac{y}{x}\qquad tan\left( \frac{3\pi }{4} \right)=\cfrac{1}{x}\implies \cfrac{sin\left( \frac{3\pi }{4} \right)}{cos\left( \frac{3\pi }{4} \right)}=\cfrac{1}{x}\implies \cfrac{\frac{\sqrt{2}}{2}}{-\frac{\sqrt{2}}{2}}=\cfrac{1}{x}&#10;\\\\\\&#10;-1=\cfrac{1}{x}\implies x=-1\qquad \qquad \boxed{(-1,1)}
8 0
3 years ago
An official for a national dog show studies the characteristics of one breed of dog, the Dandie Dinmont Terrier. Two common meas
LUCKY_DIMON [66]

Answerb:

Step-by-step explanation:

8 0
3 years ago
Sean asked 10 of his classmates the amount of their weekly allowance. He recorded the information in this table. $15 $15 $22 $14
Anarel [89]

The interquartile range = Third quartile - First quartile = 22 - 15 = 7

The range = 25 - 12 = 13

<h3>What is the Interquartile Range (IQR) and Range ofa Data?</h3>

Range = largest data value - the least data value

Interquartile range = Q3 - Q1

Given the following weekly allowance of Sean's classmates as, 15, 15, 22, 14, 12, 24, 16, 25, 15, 15:

Third quartile (Q3) = 22

First quartile (Q1) = 15

Interquartile range = 22 - 15 = 7

Range = 25 - 12 = 13

Learn more about trhe interquartile range on:

brainly.com/question/4102829

#SPJ1

8 0
2 years ago
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