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nalin [4]
3 years ago
10

Can someone help me with question 5-9

Mathematics
1 answer:
Tju [1.3M]3 years ago
7 0
If a circle is equal to 365°, take 365° and multiply is by each percentage:
Potatoes - 365° x .088 = 32.12 = 32°
Green Beans - 365 x .119 = 43.435 = 43°
Corn - 365 x .151 = 55.115 = 55°
Carrots - 365 x .108 = 39.42 = 39°
Broccoli - 365 x .197 = 71.905 = 72°
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Which statements accurately describe the function f(x) = 3(18)*? Select three options.
Yanka [14]

Answer:

Step-by-step explanation:

Without the variable x, your "f(x) = 3(18)*" is not a function.  If you meant

f(x) = 3(18)^x, then the domain is "the set of all real numbers," and the range is (0, infinity).

the initial value is 3:  f(0) = 3(18)^0 = 3(1) = 3

7 0
3 years ago
To estimate his travel time, joe divides the distance, d, in miles by 5 less than his expected average speed, in miles per hour.
Elis [28]
<span>Distance is equal to rate times time, and time is the unknown in this instance. To find time, divide distance by rate. In this case, Joe wants to use a rate five miles per hour less than his planned speed of 75 miles per hour, which is 70. Dividing 310 miles by 70 miles per hour yields an expected travel time of 4.4 hours.</span>
4 0
3 years ago
One number is five more than another number. If the square of the smaller number is 3 more than 3 times the larger number, what
11111nata11111 [884]

Answer:

6 and 11

Step-by-step explanation:

n1 = n + 5

ns^2 = 3 + 3nb

6^2 = 3 + 3(11)

36 = 3 + 33

11 = 6 + 5

3 0
1 year ago
4. Nicole has 3,874 pieces of candy to hand
Zina [86]

Answer: 149 pieces of candy

Step-by-step explanation:

     We will divide the total number of pieces of candy by the number of students to find how many each student receives.

3,874 / 26 = 149

        Each student will receive 149 pieces of candy.

3 0
1 year ago
Read 2 more answers
Can you answer these please many thanks
givi [52]

Given: (a) 2(x+3)=2x+6 and (b) 4(y-3)=4y-12.

To find: The expanded form of the given expressions.

(c) 4(m+n)=4m+4n       (using a(b+c)=ab+ac)

(d) 3(5-q)=15-3q           (using a(b-c)=ab-ac)

(e) 5(2c+1)=10c+5          (using a(b+c)=ab+ac)

(f) 3(2x-5)=6x-15          (using a(b-c)=ab-ac)

(g) 7(4b-1)=28b-7          (using a(b-c)=ab-ac)

(h) 3(2x+y-5)=3((2x+y)-5)

⇒3(2x+y-5)=3(2x+y)-15         (using a(b-c)=ab-ac)

⇒3(2x+y-5)=6x+3y-15            (using a(b+c)=ab+ac)

(i) 2(6a-4b+3)=2((6a-4b)+3)

⇒2(6a-4b+3)=2(6a-4b)+6         (using a(b+c)=ab+ac)

⇒2(6a-4b+3)=12a-8b+6            (using a(b-c)=ab-ac)

(j)6(m+n+p)=6((m+n)+p)

⇒ 6(m+n+p)=6(m+n)+6p           (using a(b+c)=ab+ac)

⇒ 6(m+n+p)=6m+6n+6p            (using a(b+c)=ab+ac)

(k) y(y+2)=y^2+2y          (using a(b+c)=ab+ac)

(l) g(g-3)=g^2-3g           (using a(b-c)=ab-ac)

(m) n(4-n)=4n-n^2        (using a(b-c)=ab-ac)

(n) a(b+c)=ab+ac           (using a(b+c)=ab+ac)

(o) s(3s-4)=3s^2-4s        (using a(b-c)=ab-ac)

(p) 2x(x+5)=2x^2+10x     (using a(b+c)=ab+ac)

(q) 4y(x-3)=4xy-12y      (using a(b-c)=ab-ac)

(r) 5a(2b-5)=10ab-25a     (using a(b-c)=ab-ac)

(s) 4a(3b+2c)=12ab+8ac    (using a(b+c)=ab+ac)

(t) 5p(4p-5q)=20p^2-25pq    (using a(b-c)=ab-ac)

6 0
3 years ago
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