You can use elimination to solve systems of equations with 3 equations. I know how to solve systems of equatons with 3 equations, but I use a different process, I don't know how to use the elimination method.
Answer:
I think it's A: Similar - AA
Step-by-step explanation:
We know that ∠K≅∠N & ∠L≅∠P, so that gives us 2 sets of congruent angles
Answer:
Thanks, but here is a problem I'll give myself.
Problem X+2 > 3
Step-by-step explanation:
1. Take Away 2 from both sides.
2. Answer: X > 1
Answer:
4a)= 2.1m 4b)= 1.9 m 5)= 29.6º
Step-by-step explanation:
4a):
x is the opp
AB is the hyp
BC is the adj
thus,
sin32 = x/4
cross multiply, x= 4*sin32
x= 2.1196.......
x=2.1 m
4b).
x is the hyp
ac is the opp
bc is the adj
thus,
cos65=4.5/x
cross multiply, x= 4.5*cos65
x=1.9017....
x=1.9 m
5).
AB is the opp
bc is the adj
ac is the hyp
thus:
tanC= 2.1/3.7
C= tan^-1 (2.1/3.7)
C= 29.5778.....
C= 29.6º
Answer:
(x − 2)×(3x+1)
Step-by-step explanation:
We can use this method:

All I did is Subtracting x then adding x which will not affect the result because -x + x = 0