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Ilya [14]
3 years ago
5

What is the 33rd term of this arithmetic sequence?

Mathematics
1 answer:
djverab [1.8K]3 years ago
8 0
Find your formula.
Tn=-5n+17
Execute the formula for the wated term.
Tn=-5(33)+17
Tn=-148
The 33rd term of the sequence is -148.
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State the number of possible real zeros and turning points of f(x) = x7 – 6x6 + 8x5. Then determine all of the real zeros by fac
Rudiy27

Answer:

steps below

Step-by-step explanation:

f(x) = x⁷ – 6x⁶ + 8x⁵

f'(x) = 7x⁶ - 36x⁵ + 40x⁴

      = x⁴ (7x² - 36x + 40)   ... (1)

Critical point (x,y): x = 0  ,  x = (36 ± √(-36)²-4*7*40) / (2*7) = (18±2√11) / 7

x = 0   or   x = 3.5    or    x = 1.6

plug into (1): y = 0   ,  y = -394.3  ,    y = 10.1

extreme : <u>maximum (1.6 , 10.1)</u>       <u>minimum (3.5 , -394.3)</u>  ... turning points

x⁷ – 6x⁶ + 8x⁵ = x⁵ (x² - 6x + 8) = x⁵ (x-2) (x-4) =0

<u>real zeros: x = 0,   x=2,    x=4</u>

3 0
3 years ago
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JulijaS [17]

Answer:

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>

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Please solve with explanation will give BRAINLIEST and Bonus Points
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