3 years ago

B) Work out the size of one interior angle. NEED HELP WITH B thanks everyone

1 answer:

7 0

Sum of interior angles of a pentagon = 540 degrees

So 540/5 = 108 degrees
A single interior angle of a pentagon is 108 degrees

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Value of x is 9 and measure of each side is 35 units.

<u>SOLUTION: </u>

Given, Triangle QRS is an equilateral triangle.

QR is seventeen more than twice x, $\rightarrow QR = 17 + 2x$

RS is 19 less than six times x, $\rightarrow RS = 6x-19$

And QS is one less four times x, $\rightarrow QS = 4x-1$

We have to find x and measure of each side.

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Then $QR = QS \rightarrow 17 + 2x = 4x-1 \rightarrow 4x-2x = 17 + 1 \rightarrow 2x = 18 \rightarrow x = 9$

So, value of x is 9.

$\begin{array}{l}{\text { Now, } \mathrm{QR}=17+2(9)=17+18=35} \\\\ {\mathrm{RS}=6(9)-19=54-19=35} \\\\ {\mathrm{QS}=4(9)-1=36-1=35}\end{array}$

Hence, value of x is 9 and measure of each side is 35.

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