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2 years ago

If AB=48 and BC=22, then AC=?

Mathematics

2 answers:

Kazeer [188]2 years ago

7 0

Answer:

Step-by-step explanation:

If we have a line with points A, B and C, and the distance between AB is 48, and the distances between BC is 22, then the distance between AC will be the solution of adding 48+22.

(Distance AB) + (Distance BC) = (Distance AC)

48+22=70

So the answer is 70

alexandr1967 [171]2 years ago

4 0

If A, B and C are collinear, then

1) if B is between A and C:

AC = AB + BC

AC = 48 + 22 = 70

2) if C is between A and B:

AB = AC + BC

48 = AC + 22 |-22

AC = 26

3) if A is between B and C:

BC = AB + AC

22 = 48 + AC |-48

AC = - 26 < 0 FALSE

Answer:

if B is between A and C, then AC = 70

if C is between A and B, then AC = 26

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This is a piecewise function |x+3| ,x>2

marusya05 [52]

Answer:

Given: piece wise function-

f(x) = x + 3 for x < 0 and f(x) = 2x for x ≥ 0

First part of the function does not include x = 0.

In slope-intercept form,

slope(m) = 1

y-intercept = (0,3).

So, the conditions are shown in graphs 1 and 3.

Now, the second part of the function equation passes through origin as the equation is f(x) = 2x.

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Note: See picture of graph attached.

Step-by-step explanation:

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2 years ago

Write 0.00000000018 in a scientific notation

Ugo [173]

Answer:

$1.8*10^{-10}$

Step-by-step explanation:

To find the number in scientific notation you want to find how many times you have to move the decimal to get the decimal to be right after the first non-zero number. If you move to the left the exponent is positive and if you move it to the right the exponent is negative. The answer would be $1.8*10^{-10}$ .

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2 years ago

Suppose that X has a discrete uniform distribution on the integers 0 through 9. Determine the mean, variance, and standard devia

Anna35 [415]

With 10 integers available, $X$ has PMF

$\mathbb P(X=x)=\begin{cases}\dfrac1{10}&\text{for }0\le x\le9,x\in\mathbb Z\\\\0&\text{otherwise}\end{cases}$

We're interested in the statistics of the new random variable $Y=5X$ . To do this, we need to know the PMF for $Y$ . This isn't too hard to find.

$\mathbb P(Y=y)=\mathbb P(5X=y)=\mathbb P\left(X=\dfrac y5\right)$

Since the PMF for $X$ gives a value of $\dfrac1{10}$ whenever $x$ is an integer between 0 and 9, it follows that $\dfrac y5$ must also be an integer for the PMF to give the identical value of $\dfrac1{10}$ . This means

$\mathbb P(Y=y)=\begin{cases}\dfrac1{10}&\text{for }y\in\{0,5,\ldots,45\}\\\\0&\text{otherwise}\end{cases}$

Now the mean (expectation) is

$\mathbb E(Y)=\displaystyle\sum_yy\mathbb P(Y=y)=\frac1{10}\sum_{y\in\{0,\ldots,45\}}y$
$\mathbb E(Y)=\dfrac{225}{10}=22.5$

The variance would be

$\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$
$\mathbb V(X)=\displaystyle\sum_yy^2\mathbb P(Y=y)-\mathbb E(Y)^2$
$\mathbb V(X)=\displaystyle\frac1{10}\sum_{y\in\{0,\ldots,45\}}y^2-\left(\frac{225}{10}\right)^2$
$\mathbb V(X)=\dfrac{7125}{10}-\dfrac{50625}{100}=206.25$

The standard deviation is the square root of the variance, so you have

$\sqrt{\mathbb V(X)}=\sqrt{206.25}\approx14.3614$

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3 years ago

The mean score on a biology exam taken by all undergraduate students in a college in a particular year is 67.8 with a standard d

Ket [755]

In this question we simple wish to calculate the standard error and margin of error from the population. This can be done purely using the standard deviation and sample size.

Standard error
= std dev / (SQRT) n
= 11.5 / SQRT of 70
= 11.5 / 8.366
= 1.374

Margin of error is the standard error multiplied by a Z value that correspondence to a confidence percentage. At a 95% confidence the Z value is 1.96. Therefore
MOE = 1.96 x 1.374 = 2.69

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