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3 years ago

What is the perimeter of a 30 2/3 yd. by 25 1/2 yd. field?

Mathematics

1 answer:

netineya [11]3 years ago

3 0

(30 2/3 *2)+(25 1/2*2)= 61 1/3+ 51=112 1/3 yards. The answer is b

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A model rocket has upward velocity v(t) = 10t2 ft/s, t seconds after launch. Use the interval [0, 6] with n = 6 and equal subint

Over [174]

Answer:

a)550

b)910

c)730

Step-by-step explanation:

The given model is

$v(t) = 10t^2 ft/s$

Use the interval [0,6], with n=6 rectangles

Then, the interval width is

$\Delta t = \frac{b-a}{n}$

$\Delta t = \frac{6-0}{6}$ = 1

so, the sub intervals are

[0,1], [1,2], [2,3], [3,4],[4,5],[5,6]

Now evaluating the function values

$f(t_0)= f(0) = 0$

$f(t_1)= f(1) = 10$

$f(t_2)= f(2) = 40$

$f(t_3)= f(3) = 90$

$f(t_4)= f(4) = 160$

$f(t_5)= f(5) = 250$

$f(t_6)= f(6) = 360$

a) left hand sum is

L_6 = $\Delta t [f(t_0)+ f(t_1)+f(t_2)+f(t_3)+f(t_4)+f(t_5)]$

= $1 [0+ 10+40+90+160+250]$

= 550

b) right hand sum

R_6 = $\Delta t [ f(t_1)+f(t_2)+f(t_3)+f(t_4)+f(t_5)+f(t_6)]$

= $1 [10+40+90+160+250+360]$

= 910

c) average of two sums is

$\frac{L_5+R_5}{2}$

= $\frac{550+910}{2}$

=730

8 0

3 years ago

Which of the following equations could be used to solve the given equation?

HACTEHA [7]

It is the third option 16x+9=4x

8 0

3 years ago

Section 4

dybincka [34]

Answer:

A is right answer bro just see

3 0

3 years ago

(1-(-3)/9-(-3)) solve

podryga [215]

Answer:

4.33333333333

Step-by-step explanation:

4 0

3 years ago

Let log P/N=8 and log M/N=5<br><br> What is the relationship between P and M?

Radda [10]

Want to use some of the algebra rules of log's:

log(a)-log(b)= log(a/b),

so log(P/N) - log(M/N) = log( P/N:M/N) = log(P/M),

Then: 8-5 = log(P/M), log(P/M)=3.

If log here means natural logarithm (base e), then P/M = e^3,

If log here means basis 10, decimal logarithm, then P/M = 10^3 = 1000.

8 0

3 years ago