Answer:
true
Step-by-step explanation:
Answer:
7n + 9 = n² + 1
n = -1, 8
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Factoring
- Solving quadratics
Step-by-step explanation:
<u>Step 1: Set up Equation</u>
"Nine more" is + 9
"Seven times a number" is 7n
"One more" is + 1
"Square of the [same] number" is n²
7n + 9 = n² + 1
<u>Step 2: Solve for </u><em><u>n</u></em>
- Subtract 7n on both sides: 9 = n² - 7n + 1
- Subtract 9 on both sides: 0 = n² - 7n - 8
- Factor quadratic: 0 = (n - 8)(n + 1)
- Solve roots: n = -1, 8
11/15 because 3/5 converts to 9/15 so 9/15+2/15=11/15
Check the picture below.
something worth noticing 
so, we're really graphing x+2, with a hole at x = 3, however, when x = 3, we know that f(x) = 5, but but but, when x = 3, x+2 = 5, so we end up with a continuous line all the way, x ∈ ℝ, because the "hole" from the first subfunction, gets closed off by the second subfunction in the piece-wise.
Answer:
Le and nos
Step-by-step explanation: