Answer: g(h(3)) = 59
Step-by-step explanation:
Well if its x^3 I assume it is because you wrote other coefficients before the variable.
2(3) - 2 = 6-2 = 4
So 4 is the x input for h(x)
4^3 -5 = 64-5 = 59
Now that we’ve learned how to solve word problems involving the sum of consecutive integers, let’s narrow it down and this time, focus on word problems that only involve finding the sum of consecutive even integers.
But before we start delving into word problems, it’s important that we have a good understanding of what even integers, as well as consecutive even integers, are.
Even Integers
We know that even numbers are integers that can be divided exactly or evenly by 22. Thus, the general form of the even integer nn, is n = 2kn=2k, where kk is also an integer.
In other words, since even numbers are the multiples of 22, we can represent an even integer nn by 2k2k, where kk is also an integer. So if we have the even integers 1010 and 1616,
Answer:
Nopes 3²+4²≠12²
Step-by-step explanation:
12²=144
3²+4²=
9+16=25
25≠144
To make it easier to see exactly WHY 3²+4²≠12² you can spread out the numbers in the equation.
(3·3)+(4·4)≠(12·12)
When solving equations you use PEMDAS (Parenthesis Exponents Multiplication Division Addition Subtraction). You have to solve in THAT ORDER.
<span>C.
-2/3
</span><span>A.
-1/2
derp derp</span>
