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tatiyna
3 years ago
5

Divide 2 by 7 and turn into a fraction

Mathematics
1 answer:
Marizza181 [45]3 years ago
8 0
3/5 i believe. if you take 7 and divide it by 2 its 3.5. 
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C.) Are the same length

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No matter how long the rectangle is the diagonals always will measure the same length. Think about two sides of a square, they have to equal the same length because if they were not the same then the shape wouldn't be a square.

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(PLS HELP NOW WILL GIVE BRINIEST!!!!!) A figure is formed by two pairs of parallel sides that are the same length. Which type of
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Step-by-step explanation:

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Suppose you cut along a diagonal of a rhombus, a rectangle, or a square. Would you get two triangles that have the same shape an
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Does anyone know how to solve this question. Coach kunal stacks all of the tennis balls in a square pyramid. The number of tenni
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Answer:

D. 9

Step-by-step explanation:

From the question, we are given the following information:

The number of tennis balls represented by P(n), in n layers of the square pyramid is given as

P(n) = P(n - 1) + n²

In other to solve for n, we would be taking some values for n

Step 1

Let's take the first layer,

n is represented by 1

n = 1

P(1) = P(1 - 1) + 1²

P(1) = 1 tennis ball.

Step 2

Let's take the second layer

n is represented by 2

P(2) = P(2 - 1) + 2²

P(2) = P(1) + 2²

Note that: P(1) above = 1

P(2) = 1 + 2²

P(2) = 5 tennis balls

Step 3

Let's take the third layer

n is represented by 3

P(3) = P(3 - 1) + 3²

P(3) = P(3 - 1) + 3²

P(3) = P(2) + 3²

Note that: P(2) above = 5

P(3) = 5 + 3²

P(3) = 14 tennis balls

Step 4

Let's take the fourth layer

n is represented by 4

P(4) = P(4 - 1) + 4²

P(3) = P(4 - 1) + 4²

P(3) = P(3) + 4²

Note that: P(3) above = 14

P(3) = 14 + 4²

P(3) = 30 tennis balls

We can continue this process, on and on

From the above solution for the number of the tennis balls in first four layers will be: 1, 5, 14, 30,

Hence, the number of tennis balls that Coach Kunal could not have is 9.

7 0
3 years ago
A decorative fish tank is in the shape of a right rectangular prism is shown in the diagram.
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