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Makovka662 [10]
3 years ago
13

In the following four questions, we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the pa

th between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108meters/sec, and the distance between source and destination is 10,000 km.Initially suppose there is only one link between source and destination. Also suppose that the entire MP3 file is sent as one packet. What is the transmission delay?Referring to the above question, what is the end-to-end delay (transmission delay plus propagation delay)?Now suppose there are two links between source and destination, with one router connecting the two links. Each link is 5,000 km long. Again suppose the MP3 file is sent as one packet. Suppose there is no congestion, so that the packet is transmitted onto the second link as soon as the router receives the entire packet. What is the end-to-end delay?Now suppose that the MP3 file is broken into 3 packets, each of 10 Mbits. Use the same setup as in question 3 above. Ignore headers that may be added to these packets. Also ignore router processing delays. Assuming store and forward packet switching at the router, what is the end-to-end delay?
Computers and Technology
1 answer:
pantera1 [17]3 years ago
6 0

Answer:

1)we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. Initially suppose there is only one link between source and destination. Also suppose that the entire MP3 file is sent as one packet. The TRANSMISSION DELAY is:

3 Seconds

2)

we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. The END TO END DELAY(transmission delay plus propagation delay) is

3.05 seconds

3)

we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. how many bits will the source have transmitted when the first bit arrives at the destination.

500,000 bits

4)

we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. Now suppose there are two links between source and destination, with one router connecting the two links. Each link is 5,000 km long. Again suppose the MP3 file is sent as one packet. Suppose there is no congestion, so that the packet is transmitted onto the second link as soon as the router receives the entire packet. The end-to-end delay is

6.1 seconds

5)

we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. Now suppose that the MP3 file is broken into 3 packets, each of 10 Mbits. Ignore headers that may be added to these packets. Also ignore router processing delays. Assuming store and forward packet switching at the router, the total delay is

4.05 seconds

6)

we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. Now suppose there is only one link between source and destination, and there are 10 TDM channels in the link. The MP3 file is sent over one of the channels. The end-to-end delay is

30.05 seconds

7)

we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. Now suppose there is only one link between source and destination, and there are 10 FDM channels in the link. The MP3 file is sent over one of the channels. The end-to-end delay is

30.05 seconds

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vesna_86 [32]

Answer:

   public static int[] listLengthOfAllWords(String [] wordArray){

       int[] intArray = new int[wordArray.length];

       for (int i=0; i<intArray.length; i++){

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       }

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Explanation:

  1. Declare the method to return an array of ints and accept an array of string as a parameter
  2. within the method declare an array of integers with same length as the string array received as a parameter.
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A Complete Java program with a call to the method is given below

<em>import java.util.Arrays;</em>

<em>import java.util.Scanner;</em>

<em>public class ANot {</em>

<em>    public static void main(String[] args) {</em>

<em>       String []wordArray = {"John", "James", "David", "Peter", "Davidson"};</em>

<em>        System.out.println(Arrays.toString(listLengthOfAllWords(wordArray)));</em>

<em>        }</em>

<em>    public static int[] listLengthOfAllWords(String [] wordArray){</em>

<em>        int[] intArray = new int[wordArray.length];</em>

<em>        for (int i=0; i<wordArray.length; i++){</em>

<em>            int lenOfWord = wordArray[i].length();</em>

<em>            intArray[i]=lenOfWord;</em>

<em>        }</em>

<em>        return intArray;</em>

<em>    }</em>

<em>}</em>

This program gives the following array as output: [4, 5, 5, 5, 8]

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