Answer:
i think it is y = -4/5x + 4
Step-by-step explanation:
4x + 5y = 20
Subtract 4x on both sides
5y = -4x + 20
Divide 5 on both sides
y = -4/5x + 4
<h3>Weight of train A is 465 tons and weight of train B is 73 tons</h3>
<em><u>Solution:</u></em>
Let "a" be the weight of train A
Let "b" be the weight of train B
<em><u>Train A and Train B, weigh a total of 538 tons</u></em>
Therefore,
a + b = 538 -------- eqn 1
Train A is heavier than Train B
<em><u>The difference of their weights is 392 tons</u></em>
Therefore,
a - b = 392 ------- eqn 2
Solve eqn 1 and eqn 2
Add eqn 1 and eqn 2
a + b = 538
a - b = 392
( + ) -----------
2a = 930
a = 465
<em><u>Substitute a = 465 in eqn 1</u></em>
465 + b = 538
b = 538 - 465
b = 73
Thus, weight of train A is 465 tons and weight of train B is 73 tons
Answer:
t=6
Step-by-step explanation:
ground height = 0
(are you sure your formula is correct? isn't it - 16t²?)
if h=16t² +64t+192 is true then
16t² +64t+192 = 0
t² + 4t + 12 = 0
t = (-4 ± √(4² - 4*12)) / 2*1 = (-4 ± √-32) / 2 = -2 ± 2√-2
There is no solution of t
if it is h= - 16t² +64t+192
0 =- 16t² + 64t + 192
t² - 4t - 12 = 0
(t + 2) (t -6) = 0
t should be positive
t = 6 sec
Answer:
-12
Step-by-step explanation:
