Question

Which of the following illustrates a phase shift?

Answer 1

Answer: The correct answer would be AAAAAAAAAAAAA!!!!

Answer 2

Answer:

A. y = -2 - cos(x-π)

Explanation:

The general form of the trig equation is:

y = A sin (Bx + C) + D

where:

A is the amplitude

$\frac{2\pi}{B}$ is the period

$\frac{-C}{B}$ is the phase shift

D is the vertical shift

Now, let's check the choices:

A. y = -2 - cos(x-π)

$\frac{-C}{B} = \frac{\pi}{1} = \pi$

Therefore, the function has a phase shift of π

B. y = 3 cos(4x)

$\frac{-C}{B} = \frac{0}{4} = 0$

Therefore, the function has no phase shift

C. y = tan(2x)

$\frac{-C}{B} = \frac{0}{2} = 0$

Therefore, the function has no phase shift

D. y = 1 + sin(x)

$\frac{-C}{B} = \frac{0}{1} = 0$

Therefore, the function has no phase shift

Based on the above, the correct answer is A

Hope this helps :)