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Sholpan [36]
4 years ago
8

I need help with this!! Please

Mathematics
1 answer:
HACTEHA [7]4 years ago
6 0

Answer:

yes

Step-by-step explanation:

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Point slope equation slope=8 point on line is (5,6)​
Assoli18 [71]

Answer:

c

Step-by-step explanation:

8 0
4 years ago
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Which of the following represents two lines that are coplanar and do not intersect?
OverLord2011 [107]

Question:

Which of the following represents two lines that are coplanar and do not intersect?

A. Perpendicular

B. Skew

C. Parallel

D. Intersecting

Answer:

Two lines that are co -planar and do not intersect is  Parallel.

Step-by-step explanation:

Two lines are said to be parallel if they lie in the same plane, and are the same distance apart over their entire length.Each line has many parallels. Any line that has the same slope as the original will never intersect with it.  Hence Parallel Lines would never cross, even if extended forever. Technically parallel lines are two coplanar which means they share the same plane or they're in the same plane that never intersect

7 0
3 years ago
Solve for X: 5X +2 = 4X -9
RUDIKE [14]

Answer:5X+2=4X-9\quad :\quad X=-11

Step-by-step explanation:

5X+2=4X-9

5X+2-2=4X-9-2

5X=4X-11

5X-4X=4X-11-4X

X=-11

4 0
4 years ago
Read 2 more answers
FIRST GETS BRAINIEST Write a story problem in which you would have to multiply 5 × (-1/3)
AveGali [126]

Answer:

5 students from Westville Elementary school re on a field trip. They come to a hot dog stand and no one has money. One student's parents has a tab at the hot dog stand. So the student, along with the four others, decide to order food and put it on the tab. Each hot dog is 1/3 of a dollar. They would like to know how much they are in debt.

5 times the negative (-1/3) for each hot dog.

-1 and 2/3 dollars

Glad I was able to help!!

4 0
4 years ago
Read 2 more answers
3. What are the roots of the polynomial y = x³ - 8?
zzz [600]

Step-by-step explanation:

x^3 is a perfect cube, 8 is a perfect cube, so we use difference of cubes.

{a}^{3}  -  {b}^{3}  = (a - b)( {a}^{2}  + ab +  {b}^{2} )

Cube root of x^3 is x.

Cube root of 8 is 2

So

a=x

b= 2.

(x - 2)( {x}^{2}  - 2x + 4)

Set these equations equal to zero

x - 2 = 0

x = 2

{x}^{2}  - 2x + 4 = 0

If we do the discriminant, we get a negative answer so we would have two imaginary solutions,

Thus the only real root is 2.

If you want imaginary solutions, apply the quadratic formula.

1 + i  \sqrt{ 3 }

and

1 - i \sqrt{3}

4 0
2 years ago
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