Answer:1 inch = 0.0833333 feet so 74 x 0.0833333 = 6.16667
Step-by-step explanation:
Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
Answer:
50
Step-by-step explanation:
Because of supplementary angles that line has to equal to 180
180-75 = 105
so 105 = (2x + 5)
you can subtract 5 from each side and get
100 = (2x)
then divide each side by 2 and you get
x = 50
you can check it by doing (2 x 50 + 5)
2 x 50 = 100 + 5 = 105 + 75 = 180
