Question

Area and perimeter of geometric functions

Answer 1

Answer:

C. 60

Step-by-step explanation:

From triangle ADB,

$|AD|^2+|BD|^2=|AB|^2$

$|AD|^2+16^2=20^2$

$|AD|^2=20^2-16^2$

$|AD|^2=400-256$

$|AD|^2=144$

$|AD|=\sqrt{144}$

$|AD|=12$

From triangle ADC,

$|CD|^2+12^2=15^2$

$|CD|^2+144=225$

$|CD|^2=225-144$

$|CD|^2=81$

$|CD|=9$

The perimeter is the distance around the figure.

The perimeter

$=15+20+16+9$

$=60$

Answer 2

Answer: OPTION C

Step-by-step explanation:

Calculate the height  AD with Pythagorean Theorem:

$AD=\sqrt{20^{2}-16^{2}}=12$

Calculate the base CD  with Pythagorean Theorem:

$CD=\sqrt{15^{2}-12^{2}}=9$

The perimeter is the sum of all the sides, therefore the perimeter is:

$P=9+15+16+20=60$