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Marina CMI [18]
3 years ago
13

PLSSSS HELP ME WITH THIS QUESTION!!!

Mathematics
2 answers:
AysviL [449]3 years ago
7 0

Given,  

∠AOE = 30°

∠DOB = 40°

So, ∠EOD = 180 - (30+40)           [angles on a straight line]

                =  180 - 70

                =  110

∠EOD = ∠COF                             [ vertically opposite angle]

∴ ∠COF = 110°

katen-ka-za [31]3 years ago
4 0
91°-32°=
59°
The line EF total angles must equal 180°. Therefore angle EOB is 89°, (180-91). Then line AB must also equal 180°. And angle EOB is 89° and angle COA is 32°. Take 89+32 which is 121. 180-121=59. Finally, that leaves angle COE with an angle measure of 59°.
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Answer:

Equate the divisor to 0

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2×=1

×=1/2

Putting onto the polynomial

f(1/2) = (1/2)³-1/2)²+3(1/2)-2

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Find the value of x.
sveticcg [70]

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3 years ago
Solve:7 +42-32-32 = 14.3-2a +7<br> A = -3<br> A= 0<br> A= 3<br> no solution
madreJ [45]

Answer:

a = 18.15

Step-by-step explanation:

7+42-32-32=14.3-2a+7

Combine like terms on the left side of the equation first. Add 7 and 42, then subtract 32 from the answer you get, then subtract 32 from that answer. This is going by order of PEMDAS.

Remember PEMDAS: (numbers 3 & 4 and numbers 5 & 6 are solved from left to right)

  1. Parentheses
  2. Exponents
  3. Multiplication
  4. Division
  5. Addition
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-15=14.3-2a+7

After combining like terms on the left side, you get -15. Now combine like terms on the right side of the equation by adding 14.3 and 7.

-15=21.3-2a

Get -2a alone by subtracting 21.3 from both sides.

-36.3=-2a

Divide both sides by -2.

a=18.15

In this equation, a should equal \boxed{18.15}.

5 0
3 years ago
If Sin 3x= Cos (x-60), find the value of x​
Kamila [148]

Answer:

x = 15

Step-by-step explanation:

Assuming 3x and x-60 are in degrees, you can use:

cos(a) = sin(a+90)

To rewrite the equation as:

sin(3x) = sin(x-60+90)

sin(3x) = sin(x+30)

3x = x+30

2x = 30

x = 15

But, solving 3x = x+30 which simplifies to x=15 is not the only solution to this equation, as you can see in below picture. Finding all solutions is a bit more work, but maybe that is not required in your case.

4 0
3 years ago
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