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expeople1 [14]
4 years ago
11

Select the most likely outcome of making only on-time minimum payments to a credit

Computers and Technology
1 answer:
Serjik [45]4 years ago
4 0
The answer is B. Your will have gone mostly towards paying interest and you will still owe the majority of the balance that you had from ago
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The correct option to the following question is an option (D) Masking.

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The following option is correct because Masking is the ability to apply mask on the value with the help of bitwise AND, OR and XOR,  

That's why, when Alison looks the Social Security Number then it looks different and this is the 9 digits of Social Security Number which is in three parts, the first part is for the area, the next part is for group number and last part is for the serial number.

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Which of the following is an Important criterion for evaluating the effctiveness of a graphic organizer
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how colorful it is how well it conveys information

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Answer first get branlest
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NAND is logically complete. Use only NAND gates to constructgate-level circuits that compute the
Drupady [299]

Answer:

Hi, for this exercise we have two laws to bear in mind:

Morgan's laws

NOT(А).NOT(В) = NOT(A) + NOT (B)

NOT(A) + NOT (B) = NOT(А).NOT(В)

And the table of the Nand

INPUT OUTPUT

A B A NAND B

0 0         1

0 1         1

1 0         1

1 1         0

Let's start!

a.

Input            OUTPUT

A       A     A NAND A

1         1             0

0        0            1

b.

Input            OUTPUT

A       B     (A NAND B ) NAND (A NAND B )

0         0            0

0         1            0

1          0             0

1          1             1

C.

Input            OUTPUT

A       B     (A NAND A ) NAND (B NAND B )

0        0           0

0        1             1

1         0            1

1          1            1

Explanation:

In the first one, we only need one input in this case A and comparing with the truth table we have the not gate

In the second case, we have to negate the AND an as we know how to build a not, we only have to make a nand in the two inputs (A, B) and the make another nand with that output.

In the third case we have that the OR is A + B and we know in base of the morgan's law that:

A + B = NOT(NOT(А).NOT(В))

So, we have to negate the two inputs and after make nand with the two inputs negated.

I hope it's help you.

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