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3 years ago

6

The Mariana Trench in The Pacific Ocean is about 36,201 feet deep. Based on these data how many feet deeper is the marina trench

than the Puerto Rico?

1 answer:

Mazyrski [523]3 years ago

8 0

Answer:

The answer is 27,493 Puerto Rico Trench Depth Deepest Point In the Atlantic Ocean

Step-by-step explanation:

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PLS HELP ME ASAP!!!!

mafiozo [28]

Answer:

20 Km per hour.

6 0

3 years ago

Help please<br> what is<br>

dsp73

Option A. is correct for the given condition.

Lets solve it through steps of range and functions,

First of all, Solve the equation:
$f(x) = |x|+5$
$= > x = -5$ (1)

$= > x = 5$ (2)

So these would be the ranges of X in between 5 and -5.

Hence option A. $R{f(x)eR [f(x) < 5}$ is correct.

Learn more about range and functions on:

https://brainly.ph/question/10400053

#SPJ10

3 0

2 years ago

How do you know whether two quantities x and y are proportional?

ANEK [815]

Answer:

I'm pretty sure it is (a)

8 0

3 years ago

Read 2 more answers

If $1000 is invested at 8% interest, compounded annually, then after n years the investment is worthan = 1000(1.08)ndollars.(a)

Luba_88 [7]

Answer:

Diverge

Step-by-step explanation:

(a)

1st year: $1000 * 1.08^1 = \$1080$

2nd year: $1000 * 1.08^2 = \$1166.4$

3rd year: $1000 * 1.08^3 = \$1259.71$

4th year: $1000 * 1.08^4 = \$1360.49$

5th year: $1000 * 1.08^5 = \$1469.33$

(b) The sequence is divergent, because if we take the derivative of the function with respect to n year:

$(1000*1.08^n)^{'} = 1000ln(n)*1.08^n$

This is a positive, meaning the slope of the function is positive. If we take the second derivative using product rule

$(1000ln(n)*1.08^n)^{'} = 1000\frac{ln(n)}{n}1.08^n$

This is also positive when n > 0. Therefore, the slope is positive and increasing. This means the sequence diverges.

5 0

3 years ago

Cos^(2)x=(cscxcosx)/(tanx+cotx)

bixtya [17]

$\cos^2 x = \dfrac{\csc x \cos x}{\tan x + \cot x}$

$\cos^2 x = \dfrac{\csc x \cos x}{\dfrac{\sin x}{\cos x} + \dfrac{\cos x}{\sin x}}$

$\cos^2 x = \dfrac{\csc x \cos x}{\frac{\sin x}{\cos x} \times 
\frac{\sin x}{\sin x} + \frac{\cos x}{\sin x} \times \frac{\cos x}{\cos 
x}}$

$\cos^2 x = \dfrac{\csc x \cos x}{\frac{\sin^2 x}{\sin x \cos x} + \frac{\cos^2 x}{\sin x \cos x}}$

$\cos^2 x = \dfrac{\csc x \cos x}{\frac{1}{\sin x \cos x}}$

$\cos^2 x = \csc x \cos x \sin x \cos x$

$\cos^2 x = \dfrac{1}{\sin x} \cos x \sin x \cos x$

$\cos^2 x = \cos^2 x$

6 0

3 years ago