this looks like confusing stuff
First, we'll set up two equations. One for the amount of each coin and another for the value of the coins.
N will represent nickels
D will represent dimes
N + D = 30
---The problem tells us that there are 30 total coins
0.05N + 0.10D = 2.95
---Nickels are worth 5 cents and dimes are worth 10 cents, and the total value of the coins is 2.95
Now that we have our equations, we need to solve for one of the variables in the first equation. I will solve for N.
N + D = 30
N = 30 - D
Then, we take that equation and substitute our new value for N into the second equation (value) and solve for D.
0.05(30 - D) + 0.10D = 2.95
1.5 - 0.05D + 0.10D = 2.95
1.5 + 0.05D = 2.95
0.05D = 1.45
D = 29
Now that we know how many dimes there are, we can plug that value into our equation for N and solve for N.
N = 30 - D
N = 30 - 29
N = 1
Therefore, there are 29 dimes and 1 nickel.
Hope this helps!
7x6=42 dimes
8x5=40 nickels
42+1=43 dimes
40+1=41 nickels
Answer:
- 4x³ - 33x² + 31x - 3
Step-by-step explanation:
Each term in the second factor is multiplied by each term in the first factor, that is
x²(- 4x + 3) + 9x(- 4x + 3) - 1 (- 4x + 3) ← distribute all 3 parenthesis
= - 4x³ + 3x² - 36x² + 27x + 4x - 3 ← collect like terms
= - 4x³ - 33x² + 31x - 3
11
Step-by-step explanation:
subtract 4 from 48 which gives you 44
then divide 4 by 44 to leave t alone
that would give you 11
t equals 11
