This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by <span>33</span> gives the next term. In other words, <span><span><span>an</span>=<span>a1</span>⋅<span>r<span>n−1</span></span></span><span><span>an</span>=<span>a1</span>⋅<span>r<span>n-1</span></span></span></span><span>.</span>
4c+c+5c = 5c+5c= 10c
I added the single c to the 4c first to get another 5c then added the two 5c together to get 10c, since all terms have a single c in them all can be combined
Answer:
At x = 4 ⇒ g(x) = f(2)
Step-by-step explanation:
* In the functions f(x) = 3x - 1 and g(x) = 2x - 3, the domain is
the values of x and the range is the values of y
∵ g(x) = f(2)
* Then you will use the range of f(x) at x = 2 to find the domain of g(x)
∵ The domain of f(x) = 2
∵ f(x) = 3x - 1
∴ f(2) = 3(2) - 1 = 6 - 1 = 5
* The range of f(x) = 5
∵ f(2) = g(x)
∴ 5 = g(x)
∵ g(x) = 2x - 3
∴ 2x - 3 = 5 ⇒ add 3 to both sides
∴ 2x = 8 ⇒ divide both sides by 2
∴ x = 4
* At x = 4 ⇒ g(x) = f(2)
12y - 7x = 5......(1 , ?)....when x = 1....so we sub 1 in for x
12y - 7(1) = 5
12y - 7 = 5
12y = 5 + 7
12y = 12
y = 12/12
y = 1........so ur y value is 1....and ur ordered pair is (1,1) <==
